Answer: c
Explanation : because it make sense the most (srry if im wrong!)
Answer: Work was 15 Joules
Explanation: Work W = force F · distance s
W = 5 N · 3 m
First, assume the order of the given reaction is n, then the rate of reaction i.e. ![\frac{dx}{dt}=k\times[A]^{n}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%3Dk%5Ctimes%5BA%5D%5E%7Bn%7D)
where, dx is change in concentration of A in small time interval dt and k is rate constant.
According to units of rate constant, the reaction is of second order.
![\frac{1}{[A]_{t}}-\frac{1}{[A]_{o}} = kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D_%7Bt%7D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_%7Bo%7D%7D%20%3D%20kt)
(second order formula)
Put the values,
t= 587.9 s
Hence, time taken is 587.9 s
To determine the number or amount of carbon dioxide produced from the equation, we have to note from the given chemical reaction that the ratios of the moles of the participating reactants and the resulting products will be obtained.
The first step to answering this item is to determine the number of moles of CH4 by dividing the given amount in grams by the molar mass. Molar mass of methane, CH4, is equal to 16 g/mol.
The first conversion factor is therefore is 16 g/mol.
