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SIZIF [17.4K]
3 years ago
13

In which of the following is the number of electrons the ion contains given correctly?

Chemistry
2 answers:
Agata [3.3K]3 years ago
7 0

B. Cl- has 17 electrons.

katrin2010 [14]3 years ago
3 0

Answer: A) K^+ has 18 electrons.

Explanation: Number of electrons in an atom equals to its atomic number. A cation is formed when electrons are lost from an atom and the anion is formed when electrons are gained by an atom.

Atomic number of K(potassium) is 19. K^+ is formed when one electron is lost from K.

K\rightarrow K^++1e^-

As one electron is lost from K to form K^+ , the number of electrons will be 18.

The atomic number of Cl(chlorine) is 17. In choice B, we have chlorine ion, Cl^- . Since it has -1 charge, the number of electrons for this ion will be 18 and not 17.

Cl+1e^-\rightarrow Cl^-

Atomic number of B(boron) is 5 means it has 5 electrons. In choice C, we have B^3^+ which is formed when 3 electrons are lost from B.

B\rightarrow B^3^++3e^-

As 3 electrons are lost, there will only 2 electrons remaining.

Atomic number of Ra(Radium) is 88 means it has 88 electrons. Ra^2^+ is formed when 2 electrons are lost from Ra.

Ra\rightarrow Ra^2^++2e^-

As two electrons are lost, there will be 86 electrons remaining.

So, the only correct choice is A. K^+ has 18 electrons.

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
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If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
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