A cargo plane can hold at most 38,000 lb. There are 35 boxes on the plane. Each box weighs 625 lb. How many additional boxes of
2 answers:
You might be interested in
well, first off, let's notice that we have a trapezoid with a rectangle inside it, so the rectangle is really "using up" area that the trapezoid already has.
now, if we just get the area of the trapezoid, and then the area of the rectangle alone, and then subtract that area of the rectangle, the rectangle will in effect be making a hole inside the trapezoid's area, and what's leftover, is the shaded section, that part the hole is not touching.
Answer:
The probability that the series lasts exactly four games is
Step-by-step explanation:
For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
We also need to know a small concept of independent events.
Independent events:
If two events, A and B, are independent, we have that:
What is the probability that the series lasts exactly four games?
This happens if A wins in 4 games of B wins in 4 games.
Probability of A winning in exactly four games:
In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:
Event A: A wins two of the first three games.
Event B: A wins the fourth game.
P(A):
A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).
P(B):
The probability that A wins any game is p, so P(B) = p.
Probability that A wins in 4:
A and B are independent, so:
Probability of B winning in exactly four games:
In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So
Event A: A wins one of the first three.
Event B: B wins the fourth game.
P(A)
P(X = 1).
P(B)
B wins each game with probability 1 - p, do P(B) = 1 - p.
Probability that B wins in 4:
A and B are independent, so:
Probability that the series lasts exactly four games:
The probability that the series lasts exactly four games is