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MissTica
3 years ago
11

Mess up my notes part 2 00:01:40And the white snapdragon will have the genotype small r and small r. Now, when the alleles combi

ne, the result is always big R and small r. So, in incomplete dominance red and white are neither dominant nor recessive. So instead, both alleles are present in the offspring, resulting in pink snapdragons.
00:02:19 So I'm going to write big R and small r. Again, you see a blending of the colors. Red plus white makes pink.
Section 4
00:00:00TEACHER: Now, let's look at another way trait involving one gene with two alleles that are inherited. Codominance is an inheritance pattern in which the alleles are neither recessive nor dominant, and both alleles are expressed in the offspring. So, an example of this inheritance pattern can be observed when a black rooster here, on the left oh,
00:00:26there goes my neighbor's rooster, is crossed with a white hen, which is in the middle. And the offspring is a chicken that has black and white feathers. That can be very annoying in the morning time. This type is what is called a speckled chicken. The speckled chicken has both white feathers from her mom and black feathers from her dad.
00:00:53Both feather colors are dominant and codominant. Now let's use a Punnett Square to show codominance. Suppose a plant with purple flowers, as you can see here, is crossed with a plant that has white flowers. The allele that produces purple flowers is capital F superscript p, so we're just going to call it Fp. And the allele that produces white flowers is capital F and superscript w, so we'll just call it Fw.
00:01:30Now notice that for both alleles, the capital F represents the allele, and the super scripts represent the colors. If we combine the alleles of the parents right here, well, what do we get? We get these genotypes, Fp and Fw. Notice that all offspring have the same genotype Fp and Fw.
00:02:05Because purple and white are neither dominant nor recessive, the offspring shows both colors, purple and white, are observed. So therefore, you get Fp and Fw. In other words, both alleles are dominant or codominant.
Physics
1 answer:
Semmy [17]3 years ago
8 0

Answer:

I dont get what your asking. If u explaint to me what your asking ill tell you the answer in the comments.

Explanation:

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What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases? a It decreases b
kupik [55]

Answer:

It remains the same

Explanation:

It remains the same. This is because the number of protons doesn't change and the number of protons determines the atomic number.

8 0
2 years ago
What type of energy is released when a firecracker explodes
Ludmilka [50]

-- Sound energy.  That's how you hear it explode.

-- Light energy.  That's how you see it in the sky.

-- Heat energy.  That's why you get burned if sparks fall on you.

-- Potential energy, as all the pieces fall to the ground.

These were all stored in it as chemical energy before it exploded.
5 0
4 years ago
Read 2 more answers
The speaker at the concert has the sound intensity level of 100 dB if we listen from the distance 5 m.How far from the speaker d
Mademuasel [1]

Answer:

28.11m far from the speaker the intensity drops to 85 dB.

Explanation:

In the equation for the Decibel scale

  (1). \: \:\beta =10 log(\dfrac{I}{I_0})

The ratio of the intensities can be written as

$ \frac{I}{I_0} = \dfrac{\frac{P}{A} }{\frac{P}{A_0} } $

\dfrac{I}{I_0} = \dfrac{A_0}{A}.

And since

A = 4\pi r^2

and

A_0 = 4 \pi r_0^2,

\dfrac{A_0}{A} = \dfrac{4 \pi r_0^2}{4 \pi r^2}  = \dfrac{r_0^2}{r^2}

meaning

\dfrac{I}{I_0} = \dfrac{r_0^2}{r^2}.

Putting this into equation (1), we get:

\boxed{ (2).\: \: \beta = 10log(\dfrac{r_0^2}{r^2})}

Now, if the intensity is 100 dB when the distance is 5 meters, we have:

100dB=10 log(\dfrac{r_02}{(5m)^2})

10= log(\dfrac{r_0^2}{25})

by taking both sides to the exponent:  

10^{10}= \dfrac{r_0^2}{25}

r^2 = 25 *10^{10}\\r = 5 *10^5

Now equation (2) becomes

\beta = 10log(\dfrac{25*10^{10}}{r^2})

when the intensity level is 85 dB we have

85 = 10log(\dfrac{25*10^{10}}{r^2})

8.5 = log(\dfrac{25*10^{10}}{r^2})

take both sides to exponents and we get:

10^{8.5} =10^{ log(\dfrac{25*10^{10}}{r^2})}

10^{8.5} =\dfrac{25*10^{10}}{r^2}

r^2 = \dfrac{25*10^{10}}{10^{8.5}}

\boxed{r = 28.11m}

Thus, 28.11m far from the speaker the intensity drops to 85 dB.

7 0
4 years ago
Male Rana catesbeiana bullfrogs are known for their loud mating call. The call is emitted not by the frog's mouth but by its ear
Sidana [21]

Answer:

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

The sound level is 84 dB

The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

8 0
3 years ago
Please answer and show work:
Vinvika [58]
The answer is c
Distance/speed=time
Therefore 4000/500=8
6 0
3 years ago
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