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Sonbull [250]
3 years ago
15

a point charge q is located at the center of a cube with edge length d. whatis the value of the flux over one face of the cube

Physics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

q/6Eo

Explanation:

See attached file pls

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When we turn on a switch it helps complete the electric circuit and the current passes from the positive to the negative in the
Schach [20]

Answer:

We don't get shocked because of the type of materials used in the switch is a poor conductor of electricity

Explanation:

Yes it is quite amazing we don't get shocked, this is because of resistance of the type of materials used in the switch (non conductors of electricity) so that when you try to put on a switch no current passes through you, mostly the material are made from plastics Or ceramics which are actually poor conductors of electricity.

5 0
3 years ago
Please I need help!!
Aleonysh [2.5K]

Answer: A

Explanation:

3 0
2 years ago
Please help!<br>Much appreciated!​
raketka [301]

Answer:

Rp = 3.04×10² Ω.

Explanation:

From the question given:

1/Rp = 1/4.5×10² Ω + 1/ 9.4×10² Ω

Rp =?

We can obtain the value of Rp as follow:

1/Rp = 1/4.5×10² + 1/ 9.4×10²

Find the least common multiple (lcm) of 4.5×10² and 9.4×10².

The result is 4.5×10² × 9.4×10²

Next, divide the result of the lcm by each denominator and multiply the result obtained with the numerator as shown below:

1/Rp = (9.4×10² + 4.5×10²) /(4.5×10²) (9.4×10²)

1/Rp = 13.9×10²/4.23×10⁵

Cross multiply

Rp × 13.9×10² = 4.23×10⁵

Divide both side by 13.9×10²

Rp = 4.23×10⁵ / 13.9×10²

Rp = 3.04×10² Ω.

6 0
4 years ago
Rank the four fundamental forces from strongest to weakest
kvasek [131]
1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity
3 0
3 years ago
When cs-137 decays, it emits gamma radiation. the energy of one photon is 1.06 × 10-13 j. what is the wavelength of this radiati
Kryger [21]
To find the solution to the problem, we would be using Planck's equation which is E = hv
Where:
E = energy
h = Planck's constant = 6.626 x 10-34 J·s
ν = frequency
Then, you’ll need a second equation which is c = λν
Where:
c = speed of light = 3 x 108 m/sec
λ = wavelength
ν = frequency
Reorder the equation to solve for frequency:ν = c/λ
Next, substitute frequency in the first equation with c/λ to get a formula you can use:
E = hν
E = hc/λ
But we are looking for the wavelength, so rearrange it more, then our final equation would be:
λ = hc / E 
λ = (6.625E-34)(3.0E8 m/s) / (1.06E-13) 
λ = 1.875E-12 m
3 0
3 years ago
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