Refer to the diagram shown below.
Let I = the moment of inertia of the wheel.
α = 0.81 rad/s², the angular acceleration
r = 0.33 m, the radius of the weel
F = 260 N, the applied tangential force
The applied torque is
T = F*r
= (260 N)*(0.33 m)
= 85.8 N-m
By definition,
T = I*α
Therefore,
I = T/α
= (85.8 N-m)/(0.81 rad/s²)
= 105.93 kg-m²
Answer: 105.93 kg-m²
Answer:

Explanation:
From the question we are told that:
Area 
Force 
Generally the equation for Pressure is mathematically given by
Pressure = Force/Area


Generally the equation for Pressure is also mathematically given by

Therefore



Answer:
9.412 rad/s.
Explanation:
Velocity is the rate of change of an object's position.
V = x/t
Where x is the distance in m
= 2.4 m
t is time taken in s
= 8.5 s
V = 2.4/8.5
= 0.2824 m/s.
Equating linear velocity and angular velocity,
V = ω*r
Where,
ω Is the angular speed in rad/s
r is the radius of the circle in m
= 3 cm
= 3cm * 1m/100 cm = 0.03 m
ω = V/r
= 0.2824/0.03
= 9.412 rad/s.