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Sonbull [250]
3 years ago
15

a point charge q is located at the center of a cube with edge length d. whatis the value of the flux over one face of the cube

Physics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

q/6Eo

Explanation:

See attached file pls

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Hằng số phổ biến chất khí
padilas [110]

Answer:

please in english......................................

Explanation:

8 0
2 years ago
A ball is thrown vertically upwards with a velocity of 30m/s. Determine the maximum height reached
padilas [110]
The maximum height reached is 45.92 m

6 0
2 years ago
If your mass is 20kg, and you stand on the scale (witch is your force), and the acceleration due to gravity is10m/s^2, what does
Phantasy [73]
Weight = (mass) x (gravity)

= 200 Newtons.

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5 0
3 years ago
Read 2 more answers
Which element of a valid contract is established by getting the signatures of all parties?
sweet [91]

The element of a valid contract which is established by getting the signatures of all parties is <u>mutual agreement</u>

<h3>What is an element of a valid contract?</h3>

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

Some elements of valid contract are:

  • Offer
  • Acceptance
  • Consideration
  • Intention to create legal relation
  • Certainty and capacity.

So therefore, the element of a valid contract which is established by getting the signatures of all parties is mutual agreement

Learn more about elements of a valid contract:

brainly.com/question/15101023

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8 0
1 year ago
A train pulls away from a station with a constant acceleration of 0.42 m/s2. A passenger arrives at a point next to the track 6.
Rina8888 [55]

Answer:

2.69 m/s

Explanation:

Hi!

First lets find the position of the train as a function of time as seen by the passenger when he arrives to the train station. For this state, the train is at a position x0 given by:

x0 = (1/2)(0.42m/s^2)*(6.4s)^2 = 8.6016 m

So, the position as a function of time is:

xT(t)=(1/2)(0.42m/s^2)t^2 + x0 = (1/2)(0.42m/s^2)t^2 + 8.6016 m

Now, if the passanger is moving at a constant velocity of V, his position as a fucntion of time is given by:

xP(t)=V*t

In order for the passenger to catch the train

xP(t)=xT(t)

(1/2)(0.42m/s^2)t^2 + 8.6016 m = V*t

To solve this equation for t we make use of the quadratic formula, which has real solutions whenever its determinat is grater than zero:

0≤ b^2-4*a*c = V^2 - 4 * ((1/2)(0.42m/s^2)) * 8.6016 m =V^2 - 7.22534(m/s)^2

This equation give us the minimum velocity the passenger must have in order to catch the train:

V^2 - 7.22534(m/s)^2 = 0

V^2 = 7.22534(m/s)^2

V = 2.6879 m/s

4 0
3 years ago
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