Answer:
g = 1.25m/s²
Explanation:
Given the following data;
Mass = 5kg
Height = 6m
Gravitational potential energy = 24J
To find the acceleration due to gravity;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;

Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
GPE = mgh
Substituting into the equation, we have;
24 = 5*6*g
24 = 30g
g = 30/24
g = 1.25m/s²
Therefore, the acceleration due to gravity on Planet X is 1.25m/s².
Answer:
uniform acceleration
Explanation:
The definition for uniform acceleration is:
if an object travels in a straight line and its velocity increases or decreases by equal amounts in equal intervals of time, then the acceleration is said to be uniform.
Hope this helps.
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In physical science, there are two types of quantity: scalar and vector. While scalar quantities only include the magnitude, vector quantities include both the magnitude and the direction. Displacement is an example of vector quantities. Therefore, it includes magnitude and direction.
Momentum is a product of mass and the velocity thus the momentum will be 5100*12 = 61200 kgm/s
Answer: 0 m
Explanation:
Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:
The trajectory is the <u>path followed by the body</u> (is a scalar quantity).
The displacement is <u>the distance in a straight line between the initial and final position</u> (is a vector quantity).
According to this, in the description Matthew's home is placed at 0 on a number line, then he moves 10 m to the park (this is the distance between the park and Mattew's home), then 15 m to the movie theatre until he finally comes back to his home (position 0). So, in this case we are talking about the <u>path followed by Matthew</u>, hence <u>his trajectory</u>.
However, if we talk about Matthew's displacement, we have to draw a straight line between Matthew's initial position (point 0) to his final position (also point 0).
Now, being this an unidimensional problem, the displacement vector for Matthew is 0 meters.