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padilas [110]
3 years ago
7

What does the double arrow in the diagram below label? ( click photo)

Physics
1 answer:
Scorpion4ik [409]3 years ago
5 0

B. The wavelength of the wave

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Which symbol and unit of measurement are used for voltage?
Keith_Richards [23]

Answer:

I should be V or E I am not sure what you mean by unit.

3 0
3 years ago
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By how much would 1500j of heat energy raise the temperature of 0.50kg of aluminum​
valentinak56 [21]

pls what is the specific heat capacity of water

7 0
2 years ago
what is the magnitude of the compression forces (assumed to be horizontal) acting on both sides of the center board that is sand
Len [333]

F = normal force by each board on each side

W = weight of the board in between acting in down direction = 95.5 N

f = frictional force in upward direction by each board

\mu = coefficient of friction = 0.663

Using equilibrium of force in Upward direction

f + f = W

f = W/2

f = 95.5/2 = 47.75 N

frictional force is given as

f = \mu F

47.75 = (0.663) F

F = 72.02 N

4 0
3 years ago
Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
El sargento Conejero toma el sol en su colchoneta, de 2 m2 de superficie, flotando en el agua de la piscina (d = 1 g/cm3 ). Si o
galben [10]

Answer:

  W = 529.2 N

Explanation:

We can solve this problem using the translational equilibrium equation, where the forces are the weight of the sergeant and the thrust of the water given by Archimedes' principle

         B - W = 0

where the thrust is

          B = ρ g V_liquid

The volume of the displaced liquid is

          V = A h

   

we substitute

         ρ g A h = W

We reduce the magnitudes to the SI system

         h = 2.7 cm = 0.027 m

         ρ = 1 g / cm3 = 1000 kg / m³

let's calculate

          W = 1000 9.8 2 0.027

          W = 529.2 N

7 0
3 years ago
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