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3 years ago

Can commas be used to separate the ones, tens and hundreds

Mathematics

2 answers:

zloy xaker [14]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

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fiasKO [112]3 years ago

7 0

Answer: no? because the comma goes after every three numbers.

You might be interested in

The touchdown to fumble ratio for Bobby Boucher was 9:2 If Bobby ran for 18 touchdowns,

Vika [28.1K]

Answer: He had 14 more touchdowns than he did fumbles.

Step-by-step explanation:

Step 1. Ok, so we need to see how many times 9 will divide into 18.

18/9=2.

Step 2. So now that we know that 9 goes into 18 two times and we know he has two fumbles for every 9 touchdowns we can multiply 2 by 2 to find out how man fumbles he had.

2*2=4

Step 3. Now to find out how many more touchdowns than fumbles he had we need to subtract his fumbles from his touchdowns.

18-4= 14. So, now we know he had 14 more touchdowns than he did fumbles.

Hope this helps!

4 0

3 years ago

Please help me with this problem Evaluate (-½·3)³

-Dominant- [34]

Answer: -27/8

Step-by-step explanation:

$\left(-\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}$

$\left(-\frac{1}{2}\cdot \:3\right)^3=-\left(\frac{1}{2}\cdot \:3\right)^3$

$=-\left(\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$\left(\frac{1}{2}\cdot \:3\right)^3=\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\frac{1}{8}\cdot \:3^3$

$=-\frac{1}{8}\cdot \:27$

$=-\frac{27}{8}$

3 0

2 years ago

The sum of two numbers is 64. One number is 8 more than the other. What are the two numbers?

lisabon 2012 [21]

Answer:

28 and 36.

Step-by-step explanation:

Alright, so we are given that the sum of two numbers is 64. Based on this, we know that we are going to be adding because the question said "the sum of two numbers is 64." Sum is the answer to an addition problem. Lets write an equation.

We need a variable, let x be the variable which is the value of the smaller number.

the equation is x+x+8=64

x= to the smaller number

x+8= to the number that is eight more than x or the smaller number.

Before we isolate for x, we need to simplify the expression by combining the like terms.

x plus x equals 2x.

Therefore, we have 2x+8=64.

Our goal is to isolate x, so we need to subtract 8 from both sides. 8 mius 8 is 0, and 64 mius 8 is 56.

Now, we have 2x=56.

We still need to isolate x by dividing both sides by 2. 2 divided by 2 is 1, so we are left with 1x or x. 56 divided by 2 is 28.

x=28.

Great, we found what x or the smaller value is.

Now, we need to find the larger number.

Substitute x as 28 into x+8 to find the number that is 8 more than the smaller number or x. You'll then get 36. If you add 36 and 28, you get 64. Also, 36 is 8 more than 28, so this answer is correct.

Hope this helps!

4 0

3 years ago

PLEASE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Roman55 [17]

Answer:

Step-by-step explanation:

if these are fractions than its A.

2x-4=2

4x-5=5/4

6 0

2 years ago

Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of

grin007 [14]

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

0.79 g/cm³

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

$Density = \dfrac{Mass}{Volume}$

Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

dense object will float on a dense object

The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

Density of Lego > Density of oil

The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

Therefore, the possible density of the oil is 0.79 g/cm³

Learn more here:

brainly.com/question/12864420

6 0

2 years ago