The reason why you can’t divide zero us because zero is an undefined number. Dividing is breaking something into group and you simply can't break anything if it's not there.
Take the 28 and tern it into -28 and do it on both sides, -28 + 28 = 0, -28 + -1 = -30.
Sence x represents one aka any number you will add x with 11 and you will get 12x^2
Now you have to divide 12 on both sides, 12 divided by 12 is 1 so it eliminates it, 12 divided by -30 = -2.5, so then X = -2.5, and that should be right
I hope this helps! =)
Answer:
what is the question
Step-by-step explanation:
Answer:
see the explanation
Step-by-step explanation:
we know that
The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity.
The degree and the leading coefficient of a polynomial function determine the end behavior of the graph
In this problem
we have
![f)x)=x^2+4x+3](https://tex.z-dn.net/?f=f%29x%29%3Dx%5E2%2B4x%2B3)
Is a vertical parabola open upward (the vertex is a minimum)
The degree of the function is even (2) and the leading coefficient is positive.
So,
the end behavior is:
f(x)→+∞, as x→−∞
f(x)→+∞, as x→+∞