Y=(3[1]+7)^2
y=(10)^2
y=100
The area <em>A</em> of a trapezoid with height <em>h</em> and bases <em>b</em>₁ and <em>b</em>₂ is equal to the average of the bases times the height:
<em>A</em> = (<em>b</em>₁ + <em>b</em>₂) <em>h</em> / 2
We're given <em>A</em> = 864, <em>h</em> = 24, and one of the bases has length 30, so
864 = (<em>b</em>₁ + 30) 24 / 2
864 = (<em>b</em>₁ + 30) 12
864 = (<em>b</em>₁ + 30) 12
72 = <em>b</em>₁ + 30
<em>b</em>₁ = 42
Answer:
137
Step-by-step explanation:
because you have to add the nubers
The Pythagorean Theorem states that a triangle's hypotenuse is equal to the square's of the other two sides of the triangle.
a² + b² = c<span>²
a = side of triangle
b = other side of triangle
c = hypotenuse (squared)
Find the square root to find the accurate length of the hypotenuse.</span>
Sin θ = opposite leg/hypotenuse
csc θ = hypotenuse /opposite leg =8/7
cot <span>θ = adjacent leg/opposite leg
hypotenuse =8
opposite leg =7
We need to find adjacent leg.
(Opposite leg)² +(adjacent leg)² = hypotenuse²
7² + </span>(adjacent leg)² =8²
(adjacent leg)² = 64 - 49
(adjacent leg)² = 15
adjacent leg=+/-√15
<span>WE need only positive root,
so </span>adjacent leg =√15
cot θ = √15/7 or 0.5533<span>
</span>
