What is 75.2515 rounded to the nearest tenth ?????

You pay your brother $35 that you owe him. The same week you earn $42 dog sitting for the neighbors. Can you help me write an eq

Zina [86]

Its either 42-35 or -35+42

7 0

3 years ago

June mad 10 origami birds in 30 minutes Dylan made 4 origami birds in 10 minutes who was faster

Hitman42 [59]

Answer:

Dylan

Step-by-step explanation:

Rate of Origami Making

1) June

= 10/30

= 1/3 origami birds per minute

2) Dylan

= 4/10

= 2/5 origami birds per minute

2/5 > 1/3

So Dylan was faster.

8 0

2 years ago

PLEASE HELP 13 points BRAINLIEST and thanks and 5 star rating.

djyliett [7]

Answer:6over2

Step-by-step explanation:

8 0

3 years ago

Suppose you take a simple random sample of size n=175 from the population of Reese's Pieces, still assuming that 45% of this pop

Gnesinka [82]

Answer:

The probability is $P(0.35$

Step-by-step explanation:

From the question we are told that

The sample size is n = 175

The population proportion is p = 0.45

Generally the mean of the sampling distribution is $\mu_{x} = 0.45$

Generally the standard deviation is mathematically represented as

$\sigma_{x} = \sqrt{\frac{p (1-p)}{n} }$

=> $\sigma_{x} = \sqrt{\frac{0.45 (1-0.45)}{175} }$

=> $\sigma_{x} = 0.0376$

Generally the probability of that the sample proportion of orange candies will be between 0.35 and 0.55 is

$P(0.35 < X < 0.55) = P( \frac{0.35 - 0.45}{0.0376} < \frac{X -\mu_{x}}{\sigma_{x}} < \frac{0.55 - 0.45}{0.0376} )$

=> $P(0.35$

Generally $\frac{X - \mu_{x}}{\sigma_{x}} = Z (The \ standardized \ value \ of X)$

So

$P(0.35$

=> $P(0.35$

From the z-table

$P( Z< 2.6595 ) = 0.99609$

and

$P( Z< - 2.6595 ) = 0.0039128$

So

$P(0.35$

=> $P(0.35$

3 0

3 years ago

Many companies use well-known celebrities as spokespersons in their TV advertisements. A study was conducted to determine whethe

s2008m [1.1K]

Answer:

There is enough evidence to support the claim that the proportion of brand awareness of female TV viewers and the gender of the spokesperson are not independent (P-value = 0.01537).

Step-by-step explanation:

<em>The question is incomplete: the picture attached gives the missing sample data.</em>

This is a hypothesis test for the difference between proportions.

The claim that is going to be stated in the alternative hypothesis is that the proportion of brand awareness of female TV viewers and the gender of the spokesperson are not independent. This means that the proportions differ significantly.

Then, the null and alternative hypothesis can be written as:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1 (Male celebrity), of size n1=150 has a proportion of p1=0.273.

$p_1=X_1/n_1=41/150=0.273$

The sample 2 (Female celebrity), of size n2=150 has a proportion of p2=0.407.

$p_2=X_2/n_2=61/150=0.407$

The difference between proportions is (p1-p2)=-0.133.

$p_d=p_1-p_2=0.273-0.407=-0.133$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{41+61.05}{150+150}=\dfrac{102}{300}=0.34$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.34*0.66}{150}+\dfrac{0.34*0.66}{150}}\\\\\\s_{p1-p2}=\sqrt{0.001496+0.001496}=\sqrt{0.002992}=0.055$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.133-0}{0.055}=\dfrac{-0.133}{0.055}=-2.44$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(z$

As the P-value (0.01537) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of brand awareness of female TV viewers and the gender of the spokesperson are not independent (the proportions differ).

6 0

3 years ago