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Mademuasel [1]
3 years ago
5

Which one of the following statements about s orbitals is incorrect ?

Chemistry
1 answer:
Ilya [14]3 years ago
6 0
Where are the statements??
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Rutherford bombarded gold foil with alpha (a) particles and found that a small percentage of the particles were deflected. Which
Alex73 [517]

Answer:

The presence of neutrons

Explanation:

Based on gold foil experiments, Rutherford proposed a atomic model known as Rutherford'd model or nuclear model or planetary model of the atom.

As per this model, most of the mass of the atom is concentrated in the center of the atom known as nucleus.

Electrons revolve around it same as planet revolve around sun.

Since, neutrons had not been discovered at the time of Rutherford'd model, therefore, as per the Rutherford'd model, nucleus is only made of protons.

Therefore, the correct option is option B

8 0
3 years ago
What is the independent variable of Smithers experience?
amm1812

Answer:

Smithers thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers each and assigns each group the same task (in this case, they're ... Group A is given the special juice to drink while they work. Group ... 1. Control Group. Group B. 2. Independent Variable. volume of special juice.

Explanation:

8 0
3 years ago
What is the number of protons in a neutral atom with 31 electrons and 38 neutrons?
PSYCHO15rus [73]

31

I think. Protons and electrons share the same number as well as the atomic number.

5 0
2 years ago
Read 2 more answers
How many atoms of N are in 0.82 g of NaNO3? ( molar conversion)
VMariaS [17]

The number of atoms N = 5.8 x 10²¹

<h3>Further explanation</h3>

A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12  

1 mole = 6.02.10²³ particles  

mass of N in 0.82 g of NaNO₃ (MW NaNO₃: 85 g/mol) :

\tt mass~N=\dfrac{Ar~N}{MW~NaNO_3}\times mass~NaNO_3\\\\mass~N=\dfrac{14}{85}\times 0.82\\\\mass~N=0.135~g

moles of N :

\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{0.135}{14}=0.0096

The number of atoms N :

\tt N=n\times No\\\\N=0.0096\times 6.02\times 10^{23}\\\\N=5.8\times 10^{21}~atoms

4 0
3 years ago
If an object has a density of 25 g/cm and a mass of 100 grams, what is its volume? O 40 cm3 0.25 cm 4 cm3 125 cm3​
xz_007 [3.2K]
<h3>Answer:</h3>

4 cm³

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Chemistry</u>

<u>Gas Laws</u>

Density = Mass over Volume

  • D = m/V
<h3>Explanation:</h3>

<u>Step 1: Define</u>

D = 25 g/cm³

m = 100 g

<u>Step 2: Solve for </u><em><u>V</u></em>

  1. Substitute variables [D]:                    \displaystyle 25 \ g/cm^3 = \frac{100 \ g}{V}
  2. Multiply <em>V</em> on both sides:                  \displaystyle V(25 g/cm^3) = 100 \ g
  3. Isolate <em>V</em>:                                            \displaystyle V = 4 \ cm^3
8 0
3 years ago
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