The question is incomplete, here is the complete question.
A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of copper fluoride in the solution is 
<u>Explanation:</u>
To calculate the molarity of solute, we use the equation:

We are given:
Given mass of copper (II) fluoride = 0.0498 g
Molar mass of copper (II) fluoride = 101.54 g/mol
Volume of solution = 100.0 mL
Putting values in above equation, we get:

Hence, the concentration of copper fluoride in the solution is 
Answer:
D.+1°e symbol represents a type of radiation that has the same mass as an electron and a positive charge.
Chemical energy, electrical energy, and heat energy
Answer:
The isoelectric point is that the <u>pH </u>at which the compound is in an electronically neutral form.
For diss equations<u>, p</u>lease find them in the enclosed file.
The pIs of 2 amino acids:
- Glutamate: pI = 3,2
- Histidine: pI = 7,6
Explanation:
Formula for the pI calculation: pI = (pKa1 + pKa2)/2
Given 3 pKa :
- Acid glutamic with an acid sidechain:
Use the lower 2 pKas (corresponding with 2 -COOH groups)
pKa1 = 2,19; pKa2 = 4,25; so pI = 3,2
- Histidine with 2 amino groups:
Use the higher 2 pKas ( -COOH group and -NH= group)
pKa1 = 6; pKa2 = 9,17; so pI = 7,6
Its an atom, or molecule, [in which] the complete amount of electrons isn't equal to the complete amount of protons. (Giving the atom/molecule a positive or negative electrical charge).
If this is incorrect- I'm sorry! ^^;