Answer:
7.20 X 10^-2 gm
Explanation:
Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O. Suppose 3.24 g of hydrobromic acid is mixed with 2.3 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
HBr(aq) + NaOH (S)-----------> NaBr (aq) + H20
mol wt of HBr = 1 + 79.9 = 80.9
3,24 gm of HBr = 3.24/80.9 = 0.00400moles = 4.00 X 10^-3 moles
mol wt of NaOH = 23.0 + 16.0 +1.01 = 40.0 gm
2.3 gm = 2.3/40.0 = 0.058 moles =5.8 X 10^-2
the reaction of HBr and NaOH is 1:1.
there are not enough moles of HBr to neutralize all of the NaOH. so
only 4.00X10 ^-3 moles of H2O can be produced
mol weight of H2O is (2 X 1.01) + 16.0 = 18.0
The maximum mass of H2O that can be produced is
18.0 X 4.00X10^-3 = 72.0/1000 =7.20 X 10^-2 gm
