Answer:
- slope: -5/3
- y-intercept: 2
- x-intercept: 6/5 = 1.2
Step-by-step explanation:
Finding the slope is perhaps easiest done by solving for y.
5x -6 = -3y . . . . subtract 3
y = -5/3x +2 . . . divide by -3
This is slope-intercept form, so we can see both the slope (the coefficient of x, -5/3) and the y-intercept (the constant, +2).
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To find the x-intercept, we set y=0 and solve for x. This might be most easily done using the original equation:
5x -3 = 0 +3 . . . . set y = 0
5x = 6 . . . . . . . . . add 3 to get the x-term by itself
x = 6/5 = 1.2 . . . . divide by the coefficient of x. This is the x-intercept.
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Slope = -5/3
y-intercept = 2
x-intercept = 6/5
Answer:
Step-by-step explanation:
"mix one cup of vinegar with one gallon of water"
1 cup = 8oz; one/4 cup = 2oz
You can see that quantity|the quantity|the number} of vinegar is 1/4 of the first amount,
so, we are going to would like 1/4 of the number of water, that is 1gallon = 128oz
so, 1/4 times 128oz = 32oz, that is one quart
Algebraically, 8oz : 128oz = 2oz : x
8x = 256; x = 32oz
Answer:
The answer to your question is: ∠AGE = 120°
Step-by-step explanation:
∠AGE = ?
Process
∠AGF = 60°
∠FGE = 60°
∠AGE = ∠AGF + ∠FGE = 60° + 60°
∠AGE = 120°
(a) NO.
The table will support a little over 3 ft³ of water. The volume of the aquarium is (3 ft)³ = 27 ft³, substantially larger. Hence the weight of the filled aquarium is substantially more than the table can support.
(b) NO.
The density of water (mass per volume) at a given temperature is substantially constant. That is, water is regarded as an "incompressible fluid." (Water does compress so that its density increases very slightly at extreme depth, but the effect is not measurable over a depth of 1.5 to 3 feet.) Temperature has a much greater effect on the density of water than does depth.
Answer:
x = 3, y = 19
Step-by-step explanation:
x = 3, y = 4x + 7
Substitute x =3 into the second equation
y =4*3+7
y = 12 +7
y = 19
x = 3, y = 19
