13 half-lives have passed
<h3>Further explanation
</h3>
General formulas used in decay:

T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t1/2 = 4 days
Nt=18 mg (0.01% of the original isotope)
18 mg (Nt) = 0.01% No
No = the original isotope :

The duration of decay (T) :


Half-lives passed :

The molar mass of potassium chloride is 74.5513g/mol, and the molar mass of potassium bromide is 119.002g/mol. You first need to find how many moles are in the given sample, so you divide the mass by the molar mass of potassium bromide. You don’t necessarily need to convert the mole ratio, since both the potassium chloride and potassium bromide have 2 moles in the chemical equation. Lastly, you multiply the moles at this point by the molar mass of potassium chloride, and you get your final answer.
Answer: 222.91g KCl
The answer is D. CaCl2 and H2O
P1V1=P2V2
(909/760)x=(1.99)(.45)
x=.7487L or 748.7mL
Answer:
i am not sure but is it hydrogen oxide
Explanation: