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WARRIOR [948]
3 years ago
10

Methane undergoes combustion. Which products form?

Chemistry
1 answer:
Aleksandr [31]3 years ago
3 0

<u>M</u><u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>e</u><u> </u>is a carbon compound which undergoes combustion to <em><u>release energy</u></em> and form bi production which are <u>Carbon</u><u> </u><u>dioxide</u><u> </u>( CO2 )<u> </u><u>and</u><u> </u> <u>W</u><u>ater</u> ( H20 ).

the balanced chemical equation for the reaction is : -

  • CH4 + 2 O2 =》CO2 + 2 H2O
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What is the mass of 4.99×1021 platinum atoms?
charle [14.2K]

Answer:

\boxed {\boxed {\sf 1.62 \ g \ Pt}}

Explanation:

We are asked to find the mass of a number of platinum (Pt) atoms.

<h3>1. Convert Atoms to Moles </h3>

First, we convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are platinum atoms.

We will convert using dimensional analysis so we set up a ratio using the information we know (6.022 × 10²³ platinum atoms in 1 mole of platinum).

\frac {6.022 \times 10^{23} \ atoms \ Pt}{ 1 \ mol \ Pt}

We are converting 4.99 ×10²¹ atoms of Pt to moles of Pt, so we multiply by this value.

4.99 \times 10^{21} \ atoms \ Pt *\frac {6.022 \times 10^{23} \ atoms \ Pt}{ 1 \ mol \ Pt}

Flip the ratio so the units of atoms of platinum cancel.

4.99 \times 10^{21} \ atoms \ Pt *\frac { 1 \ mol \ Pt}{6.022 \times 10^{23} \ atoms \ Pt}

4.99 \times 10^{21} *\frac { 1 \ mol \ Pt}{6.022 \times 10^{23}}

\frac { 4.99 \times 10^{21}}{6.022 \times 10^{23}} \ mol \ Pt

Divide.

0.008286283627 \ mol \ Pt

<h3>2. Convert Moles to Grams </h3>

Next, we convert moles to grams using the molar mass. This is the mass of 1 mole of a substance. This is found on the Periodic Table because it is equivalent to the atomic mass, but the units are grams per mole instead of atomic mass units. Look up platinum's molar mass.

  • Pt: 195.08 g/mol

Set up another ratio using this new information (195.08 grams of Pt in 1 mole of Pt).

\frac {195.08 \ g \ Pt}{ 1 \ mol \ Pt}

Multiply by the number of moles we just calculated.

0.008286283627 \ mol \ Pt*\frac {195.08 \ g \ Pt}{ 1 \ mol \ Pt}

The units of moles of platinum cancel.

0.008286283627*\frac {195.08 \ g \ Pt}{ 1 }

0.008286283627* {195.08 \ g \ Pt}

1.61648821\ g \ Pt

<h3>3. Round</h3>

The original measurement of atoms ( 4.99 ×10²¹ ) has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 6 in the thousandth place tells us to round the 1 up to a 2.

1.62 \ g \ Pt

There are approximately <u>1.62 grams of platinum</u> in 4.99 ×10²¹ atoms of platinum.

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Which statement correctly describes how matter is conserved in the formation of acid rain? A .There are 2nitrogenatoms in the re
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Answer:

C

Explanation:

There are 2 hydrogen atomic the reactants for every 3 hydrogen.

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If an atom has twelve electrons, how many electrons are in the n=1 energy level? How many electrons are in the n=2 energy level?
meriva

If an Atom has 12 Electrons then if it is a Neutral atom then the Atomic Number of the Atom will be 12.

The Electronic Configuration of Element with Atomic Number 12 will be :

⇒ 1s² 2s² 2p⁶ 3s²

We can notice from the Electronic Configuration that :

Given atom has 2 electrons in the 1st shell.

⇒ In the Shell : n = 1

   Number of Electrons = 2

In the similar way : Number of Electrons in 2nd shell = 2 + 6 = 8

⇒ In the Shell : n = 2

   Number of Electrons = 8

In the similar way : Number of Electrons in 3rd shell = 2

⇒ In the Shell : n = 3

   Number of Electrons = 2

4 0
3 years ago
Help Pls!!
AlexFokin [52]

The mass of carbon in 1 liter of mixture = 1.108 g

<h3>What is the mass of carbon in 1 liter of the mixture?</h3>

The mass of carbon in 1 liter of the mixture is determined as follows:

First the moles of gas is determined using the ideal gas formula:

  • n = PV/RT

n = (1 * 1)/(0.08205L * 298)

n = 0.0409 mole of total gas

mass of gas is then determined using the formula:

  • mass = density * volume

mass = 1 * 1.375

mass = 1.375 g

Let x = mass of CH₄ and y = mass of C₄H₁₀

x + y = 1.375 g

nCH₄ + nC₄H₁₀ = ntotat

moles = mass/molar mass

x + y = 1.695 => y = 1.695 - x

(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409

x/16 + (1.375 - x)/58 = 0.0409

x = 0.380 g CH₄

y = 1.375 - 0.380

y = 0.995 g of C₄H₁₀

mass of C in CH₄ = 12/16 * 0.380 = 0.285

mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823

Mass of carbon in 1 liter of mixture = 0.285 + 0.823

Mass of carbon in 1 liter of mixture = 1.108 g

In conclusion, the carbon is the major component in the mixture.

Learn more about ideal gas at: brainly.com/question/20348074

#SPJ1

6 0
2 years ago
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