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3 years ago

Explain the various modes of dispersal of seeds and fruits.

1 answer:

4 0

There are five main modes of seed dispersal: gravity, wind, ballistic, water, and by animals. Some plants are serotinous and only disperse their seeds in response to an environmental stimulus. Dispersal involves the letting go or detachment of a diaspore from the main parent plant.

Fruits and seeds dispersal is the process whereby fruits and seeds are scattered from their origin. The various ways by which fruit and seed are dispersed are known as agents of seed and fruit dispersal.

Check this link out for more information
https://qknowbooks.gitbooks.io/fruits-and-seeds/content/fruits_and_seeds_dispersal.html

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The speed of Train A is 88 km/hr, and the speed of Train B is 96 km/hr. Based on this information, which of the following statem

denis-greek [22]

Answer:

C i took that test and got 96

Explanation:

7 0

3 years ago

Ca(s)+2hno3(aq)→ca(no3)2(aq)+h2(g) identify the oxidizing agent.

aleksandr82 [10.1K]

To find for the oxidizing agent, first let us write the half reactions of this complete chemical reaction:

Ca = Ca2+ + 2e- 
2 H+ + 2e- = H2

The oxidizing agent would be the substance of the element that is reduced. We know that an element is reduced when an electron is added to it. In this case, the element being reduced is H. Therefore the oxidizing agent is HNO3.

Answer:

HNO3

8 0

3 years ago

Read 2 more answers

What do you call a large body of air? wind thunderstorm cold front air mass

Keith_Richards [23]

Answer:

thunderstrom

Explanation:

it will be answer

4 0

2 years ago

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Given 700 ml of oxygen at 7 ºC and 106.6 kPa pressure, what volume does it take at 27ºC and 66.6 kPa pressure

o-na [289]

Answer:

The volume is 1.2L

Explanation:

Initial volume (V1) = 700mL = 0.7L

Initial temperature (T1) = 7°C = (7 + 273.15)K = 280.15K

Initial pressure = 106.6kPa = 106600Pa

Final temperature (T2) = 27°C = (27 + 273.15)K = 300.15K

Final pressure (P2) = 66.6kPa = 66600Pa

Final volume (V2) = ?

To solve this question, we need to use combined gas equation which is a combination of Boyle's law, Charles Law and pressure law.

(P1 × V1) / T1 = (P2 × V2) / T2

solve for V2 by making it the subject of formula,

P1 × V1 × T2 = P2 × V2 × T1

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (106600 × 0.7 × 300.15) / (66600 × 280.15)

V2 = 22397193 / 18657990

V2 = 1.2L

The final volume of the gas is 1.2L

6 0

3 years ago

How many grams of magnesium sulfate (MgSO4) are dissolved in 0.965 L of a 0.0575 M solution?

JulsSmile [24]

<h3>Answer:</h3>

6.68 g MgSO₄

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Aqueous Solutions

Molarity = moles of solute / liters of solution

Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

0.965 L

0.0575 M

Step 2: Identify Conversions

Molar Mass of Mg - 24.31 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol

Step 3: Find MgSO₄

Substitute [M]: 0.0575 M = x / 0.965 L
Isolate x: 0.055488 mol MgSO₄ = x
Rewrite: x = 0.055488 mol MgSO₄

Step 4: Convert

$\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} )$ = 6.67959 g MgSO₄

Step 5: Check

We are given 3 sig figs as our lowest. Follow sig fig rules and round.

6.67959 g MgSO₄ ≈ 6.68 g MgSO₄

5 0

3 years ago

Explain the various modes of dispersal of seeds and fruits.​

Explain the various modes of dispersal of seeds and fruits.