3 years ago

Find the 76th term of the arithmetic sequences 16 14 12

Mathematics

1 answer:

grigory [225]3 years ago

7 0

Answer:

a₇₆ = - 134

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134

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