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3 years ago

Please answer properly and quickly.

Mathematics

1 answer:

Reika [66]3 years ago

3 0

(-8)(-2.2) = 17.6

(-3.4)(5) = -17

(-9.5)(-2) = 19

(3.8)(-5) = -19

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Semisuma lungimii bazelor este formula de calcul pentru: *

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Can I Know Which Language Is This??

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2 years ago

How many bases does a triangular pyramid have?

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3 years ago

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?

saveliy_v [14]

You can try them out and see which one works.

a: f(2) = f(1) +6 = 5+6 = 11 . . . . . . not this one

b: f(1) = f(2) -6 = -1-6 = -7 . . . . . . not this one (5 ≠ -7)

c: f(2) = f(1) - 6 = 5 - 6 = -1 . . . . . this gives the right f(2)

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_____

The appropriate choice is ...

... f(n +1) = f(n) - 6

— — — — —

You can also recognize that the next term is 6 less than the current one, so f(n+1) = f(n) - 6, which corresponds to the 3rd selection.

7 0

3 years ago

Read 2 more answers

Daryl has a total of 160 National Football League (NFL) trading cards from both the American Football Conference (AFC) and the N

Svet_ta [14]

Answer:

Step-by-step explanation:

Since A represents the number of AFC cars and N represents the number of NFC cards, and that Daryl has 160 total cards, then A+N = 160, the total number of cards. Furthermore, the number of AFC cards Daryl has is 8 more than 3 times the number of NFC cards, so A would be equal to 8 + 3N, or A = 3N + 8. The only system of equations with both of these correct equations is B.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

<u>Given expression is </u>

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

<u>Hence, </u>

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago