Because the Earth rotates through two tidal “bulges” every lunar day, coastal areas experience two high and two low tides every 24 hours and 50 minutes. ... This occurs because the moon revolves around the Earth in the same direction that the Earth is rotating on its axis.
To make the conversion we must take into account the relationship between kBq and microcuries. Both are units that represent radioactivity activity. The relationship is:
1 kilobecquerel (kBq) = 0.027027027 microcurie
Therefore, 2.6kBq will be equal to:
Answer= That activity in microcuries will be 0.070 microcuries
All you need to now is that 1L = 1000
so
Mass of 3.00L of pure water = 3000
*1.03g/
=
3090gMass of 3.00L of whole blood = 3000
*1.05g/
=
3150gMass of 3.00L of seawater = 3000
*1.00g/
=
3000g
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1 g
Mass of CO₂ = 3.14 g
Mass of H₂O = 1.29 g
Empirical formula =?
Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:
For Carbon, C:
Mass of CO₂ = 3.14 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Molar mass of C = 12 g/mol
Mass of C =?
Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂
Mass of C = 12/44 × 3.14
Mass of C = 0.86 g
For hydrogen, H:
Mass of C = 0.86 g
Mass of compound = 1 g
Mass of H =?
Mass of H = (Mass of compound) – (mass of C)
Mass of H = 1 – 0.86
Mass of H = 0.14 g
Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:
Mass of C = 0.86 g
Mass of H = 0.14 g
Divide by their molar mass
C = 0.86 / 12 = 0.07
H = 0.14 / 1 = 0.14
Divide by the smallest
C = 0.07 / 0.07 = 1
H = 0.14 / 0.07 = 2
Thus, the empirical formula of cyclopropane is CH₂
Covalent bonding occurs when pairs of electrons are by sharing by atoms.