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3 years ago

The phase of mitosis where the chromosomes replicate

1 answer:

8 0

Then, at a critical point during interphase (called the S phase), the cell duplicates its chromosomes and ensures its systems are ready for cell division. If all conditions are ideal, the cell is now ready to move into the first phase of mitosis.

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What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane

Brilliant_brown [7]

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂ ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3 moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

7 0

3 years ago

WINSTONCH [101]

Answer:

The new substance will need more energy to form its chemical bonds than the old substance will release. ... More energy will be released from the old substance than the new substance will need to form its chemical bonds.

Explanation:

This is the answer I got. Hope it's really helpful

5 0

3 years ago

Which of these elements is the most electronegative? <br> A. Sr<br> B. Na<br> C. Li<br> D. Ba

hoa [83]

Answer:

A. SR

Explanation:

SR is strongtium and is an electronegative element:))

hope this helps:))

6 0

3 years ago

Read 2 more answers

A solution is prepared by dissolving 60.0 g of sucrose, C12H22O11, in 250. g of water at 25°C. What is the vapor pressure of the

Rina8888 [55]

Answer:

23.46 mmHg is the vapor pressure for the solution

Explanation:

To solve this problem we need to apply a colligative property, which is the lowering vapor pressure.

The formula for this is: P°- P' = P° . Xm

where P' is vapor pressure for solution and P°, vapor pressure for pure solvent.

Let's determine the Xm (mole fraction for solute)

We calculate the moles of the solute and the solvent and we sum each other:

Moles of solute: 60 g /342 g/mol = 0.175 moles of sucrose

Moles of solvent: 250 g / 18 g/mol = 13.8 moles of water

Total moles: 13.8 moles + 0.175 moles = 13.975 moles

Xm for solute: 0.175 moles / 13.975 moles = 0.0125

Let's replace data in the formula: 23.76 mmHg - P' = 23.76 mmHg . 0.0125

P' = - (23.76 mmHg . 0.0125 - 23.76 mmHg) → 23.46 mmHg

7 0

3 years ago

A chemist prepares a solution of iron(III) bromide by measuring out of iron(III) bromide into a volumetric flask and filling the

ANTONII [103]

The question is incomplete, here is the complete question:

A chemist prepares a solution of iron (III) bromide $(FeBr_3)$ by measuring out 2.78 g of iron (III) bromide into a 50. mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mmol/L of the chemists iron (III) bromide solution. Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The concentration of iron(III) bromide solution is 0.19 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of iron(III) bromide = 2.78 g

Molar mass of iron(III) bromide = 298.6 g/mol

Volume of solution = 50. mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{2.78\times 1000}{298.6\times 50}\\\\\text{Molarity of solution}=0.19M$

Hence, the concentration of iron(III) bromide solution is 0.19 M

5 0

3 years ago