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3 years ago

Find the value of x show your work

Mathematics

1 answer:

madreJ [45]3 years ago

8 0

Answer:

x = 8√3

Step-by-step explanation:

Using the Pythagorean Theorem:

a² + b² = c²

x² + 8² = 16²

x² + 64 = 256

x² = 192

√x² = √192

x = √64 √3

x = 8√3

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Please answer this for me and show me the work.

Gala2k [10]

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3 years ago

In Lixue’s garden, the green pepper plants grew 5 inches in 34 month. At this rate, how many feet can they grow in one month? (L

beks73 [17]

Answer:

<h2>0.15 inches per month</h2>

Step-by-step explanation:

step one:

This problem is focused on the growth rate of a plant.

given data

the plants grow 5 inches in 34 months

and also that 1 month= 4 weeks

step two:

We can still say that

if 34 months see a growth of 5 inches

then 1 months will be X inches

cross multiply we have

X= 5/32 inches

step three:

converting this number to decimal we have

X= 0.15 inches per month

Therefore the growth rate would be

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3 years ago

A store sells a package of comic books with a poster. A poster and three comic books cost $10.50. A poster and 12 comics cost $1

NikAS [45]

answer:

there you goooo

Explanation

4 0

3 years ago

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago

V + 9 over 3= 8<br> what is v?

stira [4]

V= 15 steps are down below

6 0

2 years ago

Read 2 more answers