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4 years ago

How does current change for resistors in series? what is the equivalent resistance for resistors in series? answers?

1 answer:

8 0

The total resistance of electric circuit when resistors wired in a series is the sum of the individual resistance: each resistor in a series circuit has the same amount of current through and through it. Each resistor in a parallel circuit the same for voltage of the source applied to it.
when resistors are connected in parallel, the supply current is equal to the sum of the currents the metre resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel, they have the same potential difference is across them

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Describe how thermal energy is transferred

ikadub [295]

Answer:

Thermal energy typically flows from a warmer material to a cooler material. Generally, when thermal energy is transferred to a material, the motion of its particles speeds up and its temperature increases. There are three methods of thermal energy transfer: conduction, convection, and radiation.

Explanation:

ion know...

4 0

3 years ago

A model rocket fired vertically from the ground ascends with a constant vertical acceleration of 52.7 m/s2 for 1.41 s. its fuel

olya-2409 [2.1K]

For rectilinear motions, derived formulas all based on Newton's laws of motion are formulated. The equation for acceleration is

a = (v2-v1)/t, where v2 and v1 is the final and initial velocity of the rocket. We know that at the end of 1.41 s, the rocket comes to a stop. So, v2=0. Then, we can determine v1.

-52.7 = (0-v1)/1.41
v1 = 74.31 m/s

We can use v1 for the formula of the maximum height attained by an object thrown upwards:

Hmax = v1^2/2g = (74.31^2)/(2*9.81) = 281.42 m

The maximum height attained by the model rocket is 281.42 m.

For the amount of time for the whole flight of the model rocket, there are 3 sections to this: time at constant acceleration, time when it lost fuel and reached its maximum height and the time for the free fall.

Time at constant acceleration is given to be 1.41 s. Time when it lost fuel covers the difference of the maximum height and the distance travelled at constant acceleration.

2ax=v2^2-v1^2
2(-52.7)(x) = 0^2-74.31^2
x =52.4 m (distance it covered at constant acceleration)
Then. when it travels upwards only by a force of gravity,
d = v1(t) + 1/2*a*t^2
281.42-52.386 = (0)^2+1/2*(9.81)(t^2)
t = 6.83 s (time when it lost fuel and reached its maximum height)

Lastly, for free falling objects, the equation is
t = √2y/g = √2(281.42)/9.81 = 7.57 s

Therefore, the total time= 1.41+6.83+7.57 = 15.81 s

6 0

3 years ago

A woman (m = 45kg) is kneeling on the shoulders of a man (m = 70kg) in pair figure-skating while both are traveling at 1.5 m/s.

Temka [501]

Both the man and the woman will be experiencing the same impulse, due to Newton's third law of motion.

Explanation:

This problem considers law of conservation of momentum as well as Newton's third law of motion. As per the third law of motion, every action has an equal and opposite reaction. And the law of conservation of momentum states that the momentum is conserved after collision.

Since, here the woman is kneeling on the man, it is similar to inelastic collision where the man and woman are moving with same velocity. And as the man accelerates the woman, the woman will exhibit a forward force. While at the same time, the man will be experiencing a backward force of same magnitude as of the woman. This is in consistence with the third law of motion.

So both the man and woman will experience force of same magnitude but opposite in direction. As impulse is directly proportional to the force acting on any object in a given duration, so both the man and the woman will be experiencing the same impulse.

3 0

4 years ago

According to the article, in which TWO ways is lava similar to volcanic ash?

allochka39001 [22]

I don't see the article but i personally know that

-they both originate from volcanoes
-and ash comes from solidified lava clashing with rocks

7 0

4 years ago

A truck with a mass of 1810 kg and moving with a speed of 16.0 m/s rear-ends a 673-kg car stopped at an intersection. The collis

nadezda [96]

Answer:

velocity of truck = 7.32 m/s

velocity of truck = 23.32 m/s

Explanation:

mass of truck, M = 1810 kg

initial velocity of truck, U = 16 m/s

mass of car, m = 673 kg

initial velocity of car, u = 0 m/s

Let the final speed of the car is v and the final speed of truck is V.

Use conservation of momentum

Momentum before collision = Momentum after collision

M x U + m x 0 = M x V + m x v

1810 x 16 + 0 = 1810 V + 673 v

28960 = 1810 V + 673 v .... (1)

As the collision is elastic, so the coefficient of restitution is 1.

By using the formula

$e=\frac{v_{1}-v_{2}}{u_{2}-u_{1}}$

where, u1 be the initial velocity of truck, u2 be the initial velocity of the car, v1 be the final velocity of truck and v2 be the final velocity of car.

$1=\frac{V - v}}{0-U}$

V - v = - U

V - v = - 16

v - V = 16

v = 16 + V

Substitute in equation (1), we get

28960 = 1810 V + 673 (16 + V)

28960 = 1810 V + 10768 + 673 V

18192 = 2483 V

V = 7.32 m/s

v = 16 + 7.32 = 23.32 m/s

Thus, the velocity of truck after collision is 7.32 m/s and the velocity of car after collision is 23.32 m/s.

4 0

4 years ago