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3 years ago

If sunlight begins to warm a frozen lake, the atoms in the lakes frozen water will begin to move faster. True of False?

Physics

1 answer:

Vinvika [58]3 years ago

4 0

True, the water would eventually move from solid back to liquid form because of the heat.

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A 10-kg wagon is pulled by a force of 70 Newtons while friction provides 20 Newtons of force. How much acceleration will the wag

kkurt [141]

Answer:

5m/s²

Explanation:

Given parameters:

Mass of wagon = 10kg

Force of pull = 70N

Frictional force = 20N

Unknown:

Acceleration of the wagon = ?

Solution:

Frictional force is a force that opposes motion.

The net force is given as:

Net force = mass x acceleration

Force of pull - Frictional force = mass x acceleration

Insert the parameters and solve;

70 - 20 = 10 x acceleration

50 = 10 x acceleration

Acceleration = 5m/s²

5 0

3 years ago

Place these bodies of our solar system in the proper order of formation.

earnstyle [38]

The four inner planets, those closest to the Sun, are Mercury, Venus, Earth, and Mars. They are smaller and composed mainly of metals and rocks. The four outer planets — Jupiter, Saturn, Uranus, and Neptune — are larger and composed mostly of gases.

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3 years ago

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Is India a rich country?

Norma-Jean [14]

Explanation:

India. Total wealth: $8.9 trillion | Wealth per capita: $6,440 | India, which is the fifth-largest economy in the world, is home to 3,57,000 HNWIs and 128 billionaires.

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1 year ago

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You are traveling 70 mph (31.3 m/s) and slam on the brakes to avoid hitting another car. How far do you travel if it takes you 8

Arlecino [84]

You traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.

Given the following data:

Initial velocity, U = 31.3 m/s

Time, t = 8.5 seconds.

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find the distance traveled, we would use the second equation of motion:

Mathematically, the second equation of motion is given by the formula;

$S = ut + \frac{1}{2} at^2$

Where:

S is the distance travelled.

u is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting the parameters into the formula, we have;

$S = 31.3(8.5) + \frac{x}{y} (9.8)(8.5^2)\\\\S = 266.05 + 4.9(72.25)\\\\S = 266.05 + 354.025$

Distance, S = 620.075 meters.

Therefore, you traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.