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Fittoniya [83]
4 years ago
6

A woman (m = 45kg) is kneeling on the shoulders of a man (m = 70kg) in pair figure-skating while both are traveling at 1.5 m/s.

The man gracefully accelerates the woman forward into the air.
Which object experiences the greatest impulse, the man, the woman, or both the same?
Physics
1 answer:
Temka [501]4 years ago
3 0

Both the man and the woman will be experiencing the same impulse, due to Newton's third law of motion.

Explanation:

This problem considers law of conservation of momentum as well as Newton's third law of motion. As per the third law of motion, every action has an equal and opposite reaction. And the law of conservation of momentum states that the momentum is conserved after collision.

Since, here the woman is kneeling on the man, it is similar to inelastic collision where the man and woman are moving with same velocity. And as the man accelerates the woman, the woman will exhibit a forward force. While at the same time, the man will be experiencing a backward force of same magnitude as of the woman. This is in consistence with the third law of motion.

So both the man and woman will experience force of same magnitude but opposite in direction. As impulse is directly proportional to the force acting on any object in a given duration, so both the man and the woman will be experiencing the same impulse.

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PLEASE HELP ASAPP!!!
Sati [7]

Answer:

hello

Explanation:

for average speed the total distance is important so.

and you must convert min to hour 15 min is 1/4 or 0.25 hour

s =  \frac{x}{t}  =  \frac{12}{0.25}  = 48 \frac{km}{h}

for average velocity the straight line distance is important so

v =  \frac{d}{t}  =  \frac{8}{0.25}  = 32 \frac{km}{h}

hope you understand

7 0
2 years ago
A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}

Therefore

V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

Charge, Q is given by CV hence for the first capacitor charge will be Q_1=C_1V

Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

8 0
3 years ago
Suppose you wanted to use the Earth's magnetic field to make an AC generator at a location where the magnitude of the field is 0
Likurg_2 [28]

Answer:

The angular velocity I would have to rotate it in order to generate an emf of amplitude 1.0 V is 254.65 rad/s

Explanation:

given information:

B = 0.5 mT = 0.0005 T

N = 1000

r = 5 cm = 0.05 m

emf, ε = 1 V

according to Faraday's law

ε = -N dΦ/dt, Φ = B A

  = - N d( B A)/dt

  = - N d( B A cos ωt)/dt

   = - N B A d(cos ωt)/dt

   = N B A ω sin ωt

A = πr², so

ε = N B πr² ω sin ωt

where

ε = emf

N = number of coil turn

B = magnetic field

r = radius

ω = angular velocity

Φ = magnetic flux

emf maximum, sin ωt = 1. So,

ε = N B πr² ω

ω = ε/N B πr²

   = 1/[(1000) (0.0005) π (0.05)²

   = 254.65 rad/s

6 0
3 years ago
A +2.00nc point charge is at the origin, and a second -5.00nc point charge is on the x-axis at x = 0.800m find the magnitude of
Damm [24]
You have to reduce 2.00 an5.00 I order to use the×that=0.800
3 0
3 years ago
When you're super tired and you lose energy, what energy are you actually losing?
DIA [1.3K]

Answer:

it is chemical energy

Explanation:

that is the energy used by our body, so it is the one that we will loose. and the energy that we gain is also chemical energy

6 0
3 years ago
Read 2 more answers
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