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pychu [463]
3 years ago
12

What is the velocity of a 1.3 kg puppy with a forward momentum of 6 kg m/s​

Physics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

by using p = mv equation we can find v,

6 = 1.3 v

4.615 = v

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kirill [66]

Answer:

320 N/m

Explanation:

F = k·Δx

where

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k is the proportionality constant called the ‘spring constant’

Δx is the change in the spring’s position due to the deformation.

You need the k so

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6 0
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Anna71 [15]

\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

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∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

4 0
3 years ago
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Reil [10]

Answer:

i can see your question

pls fast

6 0
3 years ago
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(22-12)/4

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