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pychu [463]
3 years ago
12

What is the velocity of a 1.3 kg puppy with a forward momentum of 6 kg m/s​

Physics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

by using p = mv equation we can find v,

6 = 1.3 v

4.615 = v

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Explanation:

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A trumpeter is placed on a moving sidewalk that moves at a constant velocity of 4.5 m/s. A listener is standing 6.0 m in front o
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3 years ago
The gravitational force of attraction be-
Sliva [168]

Answer:

2.15 m

Explanation:

Newton's Law of Universal Gravitation:

\displaystyle F_g = G \frac{m_1 m_2}{r^2}  

  • \displaystyle F_g is the gravitational force of attraction
  • \displaystyle G is the universal gravitational constant
  • m_1 and m_2 are the two masses of the two objects
  • \displaystyle r is the distance between the centers of the two objects.

List the known values:

  • \displaystyle F_g = 3.47 \cdot 10^-^8 \ \text{N}  
  • \displaystyle G = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2}
  • \displaystyle m_1 = 44.8 \ \text{kg} \\ m_2 = 53.9 \ \text{kg}
  • \displaystyle r =\ ?

Plug these values into the equation:

  • \displaystyle 3.47 \cdot 10^-^8 \ \text{N} = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2} \frac{(44.8 \ \text{kg})(53.9 \ \text{kg})}{r^2}

Notice that the units \displaystyle \text{N}, \displaystyle \text{kg}^2, and \displaystyle \text{m} cancel out. We are left with the unit \displaystyle \text{m} for radius r.

Get rid of the units to make the problem easier to read.

  • \displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(44.8)(53.9) \ }{r^2}  

Multiply the masses together.

  • \displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(2414.72)}{r^2}

Multiply the gravitational constant and the masses together.

  • \displaystyle 3.47 \cdot 10^-^8= \frac{1.61134265\cdot 10^-^7}{r^2}

Solve for r^2 by dividing both sides by 3.47 * 10^(-8) and moving r^2 to the left.

  • \displaystyle r^2 = \frac{1.61134265\cdot 10^-^7}{3.47\cdot 10^-^8}
  • r^2 = 4.64363876

Take the square root of both sides.

  • r=2.154910383  

The students are sitting about 2.15 m apart from each other.

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2 years ago
The forward movement of orbital waves classifies them as ____ waves.
dusya [7]
The forward movement of orbital waves classifies them as progressive waves.
Orbital waves are waves that occur at the interface of two materials, with different densities e.g water and air. Ocean waves for example are all characterized by a circular motion. They combine the characteristics of longitudinal and transverse waves. Orbital waves are classified as progressive wave as the wave fronts move through a medium. 
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