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3 years ago

2. A ball tied to a pole by a rope swings in a circular path with a centripetal acceleration of 2.7 m/s. If the ball has a

Physics

1 answer:

Helga [31]3 years ago

3 0

Answer: The diameter of the circular path is 2.96m

Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.

Centripetal acceleration = 2.7m/s^2

Tangential speed = 2.0m/s

Radius = 2.0^2 / 2.7 = 4/2.7

= 1.48m

Diameter = radius*2

= 1.48*2 = 2.96m.

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The weight of a basketball with a mass of 0.5 kg is _N.

Mariana [72]

Answer:

4.9N

Explanation:

The formula for weight is F = ma.

You plug in the mass of 0.5kg and an acceleration of 9.8 to get

F = (0.5)(9.8)

F = 4.9N

3 0

3 years ago

Two books with different masses fall off the same bookshelf. As they fall,which has more kinetic energy and why

Alex

Kinetic energy E = m * v^2

<span>Since the acceleration of both books will be -neglecting air resistance - the same, the kinetic energy will be directly proportional to the mass of the book.</span>

5 0

3 years ago

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

Zepler [3.9K]

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

$v_a$ = Relative velocity of ambulance = $109\ km/h=\dfrac{109}{3.6}$

$v_w$ = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

$f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz$

The frequency of sound is 900.48925 Hz

When the wall acts like a source

$f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz$

The frequency of sound is 979.9785 Hz

4 0

3 years ago

List the differences between a radio EM wave and a visible light EM wave

just olya [345]

1). A radio EM wave has a frequency somewhere between 10 KHz and 300 GHz, whereas a visible light EM wave has a frequency somewhere between 428,000 GHz and 790,000 GHz.

2). A radio EM wave has a wavelength somewhere between 1 mm and 30 km, whereas a visible light EM wave has a wavelength somewhere between 380-700 nanometers.

7 0

3 years ago

Problem 02.061 For the given circuit, assume vS = 10 V, R1 = 9 Ω, R2 = 4 Ω, R3 = 4 Ω, R4 = 5 Ω, and R5 = 4 Ω. Reference Book &am

stich3 [128]

Answer:

Ws=8.75 Watts

Explanation:

As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:

$\frac{1}{Req45}=\frac{1}{R4}+\frac{1}{R5}$