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2 years ago

How can vectors be used in real life?

1 answer:

4 0

Using vectors can be troublesome for simple physics problems. however, when you move onto solving more difficult problems that have several variables, and the space you are dealing with is in three dimensions, using vectors is a necessity because it's not always possible to visualize the problem. but using vectors will give you a definitive answer.

few applications of vectors:
-predict the trajectory of airplanes and make sure that the airplane will not collide with some other airplane
-all simulations use vectors
-multivariable Calculus is pretty much based on vectors. without multivariable Calculus, it would have not been possible to compute many formulas.
-modeling the path a rocket will take, and supplying it the right amount of fuel so that it gets to the moon, or some other destination.

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A ring placed along y 2 + z 2 = 4, x = 0 carries a uniform charge of 5 μ C/m. ( a ) Find D at P(3,0,0) . ( b ) If two identical

GuDViN [60]

For right now idk :p

3 0

2 years ago

Recall the thermal energy model you used earlier to simulate friction with the chemistry and physics books. How does heat travel

dsp73

Answer:

due to condection of heat from pan in thermal energy according to 9th

Explanation:

7 0

2 years ago

Read 2 more answers

ow long must a simple pendulum be if it is to make exactly ten swings per second? (That is, one complete vibration takes exactly

Igoryamba

The period T of a pendulum is given by:
$T=2 \pi \sqrt{ \frac{L}{g} }$
where L is the length of the pendulum while $g=9.81 m/s^2$ is the gravitational acceleration.

In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is $T=0.200 s$ . Using this data, we can solve the previous formula to find L:
$L=g ( \frac{T}{2\pi} )^2=(9.81 m/s^2)( \frac{0.2 s}{2 \pi} )^2=1 \cdot 10^{-3} m=1 mm$

4 0

2 years ago

A square plate of copper with 55.0 cm sides has no net charge and is placed in a region of uniform electric field of 82.0 kN/C d

Alex73 [517]

Answer

given,

Side of copper plate, L = 55 cm

Electric field, E = 82 kN/C

a) Charge density,σ = ?

using expression of charge density

σ = E x ε₀

ε₀ is Permittivity of free space = 8.85 x 10⁻¹² C²/Nm²

now,

σ = 82 x 10³ x 8.85 x 10⁻¹²

σ = 725.7 x 10⁻⁹ C/m²

σ = 725.7 nC/m²

change density on the plates are 725.7 nC/m² and -725.7 nC/m²

b) Total change on each faces

Q = σ A

Q = 725.7 x 10⁻⁹ x 0.55²

Q = 219.52 nC

Hence, charges on the faces of the plate are 219.52 nC and -219.52 nC

7 0

3 years ago

I know the enthalpy of a reaction is 23kj/mol. Initially the reaction is taking place at 273 k. To what temperature do i need to

Vladimir79 [104]

Answer:

293k

Explanation:

In this question, we are asked to calculate the temperature to which the reaction must be heated to double the equilibrium constant.

To find this value, we will need to use the Van’t Hoff equation.

Please check attachment for complete solution

7 0

3 years ago