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jekas [21]
3 years ago
8

How can vectors be used in real life?

Physics
1 answer:
7nadin3 [17]3 years ago
4 0
Using vectors can be troublesome for simple physics problems. however, when you move onto solving more difficult problems that have several variables, and the space you are dealing with is in three dimensions, using vectors is a necessity because it's not always possible to visualize the problem. but using vectors will give you a definitive answer.

few applications of vectors:
-predict the trajectory of airplanes and make sure that the airplane will not collide with some other airplane
-all simulations use vectors
-multivariable Calculus is pretty much based on vectors. without multivariable Calculus, it would have not been possible to compute many formulas.
-modeling the path a rocket will take, and supplying it the right amount of fuel so that it gets to the moon, or some other destination.
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Y-> + F-> +G ->=E->

Explanation:

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Why would genetic material need to be able to reproduce
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4 years ago
The question is in the attachment. ​
sammy [17]

Answer:

Correct answer:  Yes, with acceleration a = 10 m/s²

Explanation:

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5 0
4 years ago
Metals can be described as shiny while nonmetals can be described as dull. What physical property do these terms describe? A) co
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8 0
3 years ago
Read 2 more answers
While camping in Denali National Park in Alaska, a wise camper hangs his pack of food from a rope tied between two trees, to kee
Crank

The tension in each of the ropes is 625 N.

Draw a free body diagram for the bag of food as shown in the attached diagram. Since the bag hangs from the midpoint of the rope, the rope makes equal angles θ with the horizontal. The tensions <em>T</em> in both the ropes are also equal.

Resolve the tension T in the ropes into horizontal and vertical components T cosθ and T sinθ respectively, as shown in the figure. At equilibrium,

2T sin\theta = 50 N     ......(1)

Calculate the value of sinθ  using the right angled triangles from the diagram.

sin\theta =\frac{0.06 m}{1.5 m}  =0.04

Substitute the value of sinθ in equation (1) and simplify to obtain T.

2T sin\theta = 50 N\\  T= \frac{50 N}{2 sin\theta}=\frac{50 N}{2*0.06} =   625 N

Thus the tension in the rope is 625 N.




4 0
4 years ago
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