Answer:
~181 containers filled completely, 6 eggs left over
Step-by-step explanation:
2178 ÷ 12 (a dozen, the number of eggs per container) = 181.5 containers
181 × 12 = 2,172 eggs
2,178 eggs - 2,172 = 6 eggs left over
Solve for x, like I did, then plug it in the equation for UV.
So,
(2x12) - 22 = UV
24-22 = UV
UV = 2
For this case we have the following function:
![s (V) = \sqrt [3] {V}](https://tex.z-dn.net/?f=s%20%28V%29%20%3D%20%5Csqrt%20%5B3%5D%20%7BV%7D)
This function describes the side length of the cube.
If Jason wants a cube with a minimum volume of 64 cubic centimeters, then we propose the following inequality:
![s \geq \sqrt [3] {64}](https://tex.z-dn.net/?f=s%20%5Cgeq%20%5Csqrt%20%5B3%5D%20%7B64%7D)
Rewriting we have:
![s \geq \sqrt [3] {4 ^ 3}\\s \geq4](https://tex.z-dn.net/?f=s%20%5Cgeq%20%5Csqrt%20%5B3%5D%20%7B4%20%5E%203%7D%5C%5Cs%20%5Cgeq4)
Answer:
Option B
The volume of the new rectangular prism would be 270 cubic centimeters. The reason for this is that when only one dimension is changed, the overall volume is only changed by that same relationship. Because only the height was cut in half, this would be only one of the dimensions.
First off you need to convert the numbers into mixed numbers.
1 3/7 goes to 10/7
3 2/3 goes to 11/3
Then you multiply the numerators together:
10 * 11 = 110
Do the same for the denominators:
3 * 7 = 21
Then place it into a fraction and you make the fraction positive because the signs at the start are the same:
110/21
Then you can turn it into a proper fraction:
5 5/21
