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3 years ago

HELPPP ME PLSS!!!!!!!!!!!!!!!!

Mathematics

2 answers:

11111nata11111 [884]3 years ago

7 0

Answer:

2700 cubic feet

Step-by-step explanation:

To find the volume of the figure, we need to find the separate volumes of the cuboids. The formula for the volume of a cuboid is length × breadth × height.

Volume of bigger cuboid = 11 × 10 × 22

= 2420

Volume of smaller cuboid = 10 × 4 × 7

= 280

Volume of figure = 2420 + 280

= 2700 cubic feet

Fantom [35]3 years ago

4 0

Answer:

500

Step-by-step explanation:

10*1*22=220

7*4*10=280

220+280=500

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Tema [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

the sun shines on a flagpole, causing a shadow to be cast on the ground. the distance from the base of the pole to the tip of th

kobusy [5.1K]

Answer:

30.17feet high

Step-by-step explanation:

Given the following

the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)

angle of elevation = 38°

Required

Height of the flagpole (opposite)

Using the SOH CAH TOA identity

Sin theta = opposite/hypotenuse

Sin 38 = H/49

H = 49sin38

H = 49(0.6157)

H = 30.17feet

Hence the flagpole is 30.17feet high

7 0

3 years ago

Please help me solve this for Algebra!

11111nata11111 [884]

Answer:

Step-by-step explanation:

3 0

3 years ago

HELPPPPP ASAPPPP

KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :

$h(t)=-16t^2+20t+6$ ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put $\dfrac{dh}{dt}=0$

Now put t = 0.625 in equation (1)

$h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}$

So, the maximum height of the volleyball is 12.25 feet.

5 0

4 years ago

Find the value of x to the nearest tenth

Hitman42 [59]

Answer:

a^2+b^2=c^2

6^2+6^2=72

square root of 72

=8.49(3sf)

c^2-b^2=a^2

x=3

5 0

3 years ago

Read 2 more answers