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12345 [234]
3 years ago
13

Determine the solution and indicate the restrictions on the variable.

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Subtract 20 from both sides:

-\sqrt{9-8x} =-15

Divide both sides by -1:

\sqrt{9-8x} =15

Square both sides:

9-8x=255

Subtract 9 by both sides:

-8x=216

Divide both sides by -8:

x=-27

That means that either a or b is correct and since 9/8 is positive that means it needs to bee less than 9/8 so the correct answer is B

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The probability of an event occurring is 0.08.
vova2212 [387]

Answer:

0.92

Step-by-step explanation:

always equals 1.0

1.0 - 0.08 = 0.92

7 0
3 years ago
What is the volume of the cylinder if the height is 2x+7 and the radius is x-3
shusha [124]

Answer:

Therefore the volume of the cylinder=\pi(2x^3-5x^2-24x+63)  cubic units

Step-by-step explanation:

Given height of a cylinder is (h) =2x+7

and radius  (r)= x-3

Volume of the cylinder = \pi r^2 h

                                  =\pi (x-3)^2(2x+7)

                                  =\pi (x^2-6x+9)(2x+7)

                                  =\pi (2x^3-12x^2+18x+7x^2-42x+63)

                                  =\pi(2x^3-5x^2-24x+63)  cubic units

Therefore the volume of the cylinder=\pi(2x^3-5x^2-24x+63)  cubic units

5 0
3 years ago
Fill in the blanks to make each equation true
olasank [31]

Answer:

–5 + 8 = 3. Find each sum. 1. –4 + (–8). 2. 14 + 16. 3. –43 + (–12). –12. 30. –55. 4. ... 1. Change the minus sign to a plus. 2. Find the opposite of the 2nd number. 3. Add ... –8 + –2. –3. –8. –10. 4. –3 – 24. 5. 10 – 17. 6. 13 – 9. = –3 + –24. = 10 + –17 ... 30. 5 + 4 x 3 = ____46_______. 12. (7)(9) +. 9. 3 – 20 x 3 = ____6______.

Step-by-step explanation:

5 0
3 years ago
Solve the triangle A = 2 B = 9 C =8
VARVARA [1.3K]

Answer:

\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}

Then, given the sides a=2, b=9, and c=8.

\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}

For B:

\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}

3 0
1 year ago
I need help really fast and quick
lukranit [14]

Answer:

a.

Step-by-step explanation:

8 0
4 years ago
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