4 & 6 cause one of both of them got eaten
1) Area = (b*h)/2 = (9*5)/2 = 45/2 = 22.5 (Letter A)
2) Area = b*h = 8*14 = 112 (Letter D)
3) Surface area of a prism is SA=2B+ph (B = area of the base, p = perimeter of the base, h = height)
B = 15 * 5 = 75 cm^2
p = 15 + 5 = 20 cm
SA = 2*75 + 20*7 = 150 + 140 = 290 (G)
4) V = (B*H*L)/2 = (15*7*5)/2 = 525/2 = 262.5 cm^3 (G)
5) V = 9^3 = 81 cm^3 worth of wrapping (A)
6) V = (B*H*L)/2 = (13*6*8)/2 = 312 cube feet (J)
It gave me ADGGAJ. I don't know if this is right, but I atleast tried to do something, right?
Answer:
B.) 140 is your answer for your problem
<span>Sphere Volume = </span><span> 4/3 • <span>π <span>• r³<span>
Small Balloon = </span></span></span></span><span>4/3 • 3.14<span> <span>• 3^3
</span></span></span><span>Small Balloon = 37.68 cc
Large Balloon = </span><span>4/3 • 3.14<span> • 6^3</span></span>
Large Balloon =
<span>
<span>
<span>
904.32
</span>
</span>
</span>
cc
<span>
<span>
<span>
<span>
Difference = (904.32 -</span></span></span>37.68) = </span>
<span>
<span>
<span>
866.64
</span>
</span>
</span>
cc
The larger balloon has
<span>
<span>
<span>
866.64
</span>
</span>
</span>
cc more water than the small balloon.
