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NeTakaya
3 years ago
14

Which of the following are solutions to the equation below (5x+1)^2=7? Check all that apply.

Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0

Answer:C E (apex) !!


Step-by-step explanation:


stiv31 [10]3 years ago
4 0
(5x+1)² = 7; expand: 25x² + 10x +1 = 7 or 25x² + 10x -6 = 0

Solve this quadratic for x:

x = [-b + √(b² - 4ac)]/2a and x = [-b - √(b² - 4ac)]/2a
Plug the values and you'll find :
x = (- √7 - 1)/5 (answer C)
x = (+√7 -1)/5  (answer E)

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What is the slope of a line parallel to the line y=5/2x-14?
ycow [4]

Answer:

5/2

Step-by-step explanation:

When you are finding the slope of a parallel line, the other line always has the same slope as the first line but different y intercept.

3 0
3 years ago
HELP ME PLEASE
Mashutka [201]

Answer:

9 + \frac{n}{3} - 6 = 7

Step-by-step explanation:

Given

9 + \frac{n}{3} - 6

Required

Evaluate when n = 12

Substitute 12 for n in 9 + \frac{n}{3} - 6

9 + \frac{n}{3} - 6 = 9 + \frac{12}{3} - 6

Simplify the fraction

9 + \frac{n}{3} - 6 = 9 + 4 - 6

9 + \frac{n}{3} - 6 = 7

4 0
3 years ago
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Alja [10]

9514 1404 393

Answer:

  A.  (1 2/3, 4 2/3)

Step-by-step explanation:

If you graph the equations, you see the lines intersect at the solution point:

  (x, y) = (1 2/3, 4 2/3)

7 0
3 years ago
Give the dimensions of the small prisms that can be used to pack the larger prism
Neporo4naja [7]
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4 0
3 years ago
Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of
GaryK [48]

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is KE=\frac{1}{2}mv^2

Where

KE is the kinetic energy

m is the mass

v is the velocity

  • Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
  • Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

<u>KE of 1st mass is:</u>

\frac{1}{2}mv^2

<u />

<u>KE of 2nd mass is:</u>

\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4

Hence, the kinetic energy of the 2nd mass is 4 times the first.

6 0
3 years ago
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