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3 years ago

What is the mass of one mole of C2H60 (ethanol)

Chemistry

2 answers:

irinina [24]3 years ago

7 0

One mole is equal to one mole Ethanol or 46.06844 grams

alisha [4.7K]3 years ago

3 0

Answer: 46g

Explanation:

Mole = Mass/Molar mass

Therefore, Mass of ethanol = Mole x Molar mass

Mole of ethanol = 1 mol

molar mass of ethanol = C2H5OH

= (12 x 2) + (1 x 5) + 16 + (1)

= 24 + 5 + 16 + 1

= 46 g/mol

Mass of ethanol = Mole x Molar mass

= 1 mol x 46 g/mol

= 46g

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HELP!!!!! How much does a sample of Argon weigh if it occupies 25.4 L at a pressure of 2.45 atm and a temperature of 482 K?

Artist 52 [7]

Answer:

62.82 g

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of moles of argon, R = molar gas constant, T = Temperature.

But,

Number of mole (n) = mass (m)/molar mass(m')

n = m/m'................... Equation 2

Substitute equation 2 into equation 1

PV = (m/m')RT.............. Equation 3

From the question, we were asked to find m.

There make m the subject of formula in equation 3

m = PVm'/RT.............. Equation 4

Given: P = 2.45 atm, V = 25.4 L, T = 482 K

Constant: R = 0.082 atm.dm³.K⁻¹.mol⁻¹, m' = 39.9 g/mol

Substitute these values into equation 4

m = (2.45×25.4×39.9)/(0.082×482)

m = 62.82 g.

5 0

3 years ago

CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?

Eddi Din [679]

So if we use the equation:

$CO+2H_{2}$ → $CH_{3}OH$

We can then determine the amount of $H_{2}$ needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

$208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol$

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

$\frac{2}{1} =\frac{x}{6,491.68}$

$x=12,983.36mol$

So now that we have the number of moles of $H_{2}$ that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

$12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}$

Therefore, the amount of diatomic hydrogen ( $H_{2}$ ) that is needed to produce 208kg of methanol is $2.62x10^{4}$ g.

3 0

3 years ago

Indicate whether each of the following statements about the heme-binding site in myoglobin is true or false. If you think a stat

Likurg_2 [28]

Answer:

A. True

B. False

C. False

D. True

E. False

Explanation:

A. The proximal histidine covalently binds iron.

This statement is true because the proximal histidine is covalently bonded to the fifth coordination position of iron in myoglobin

B. The distal histidine covalently binds oxygen.

This statement is false because the distal histidine interacts with the oxygen covalently bonded to the sixty coordination position of iron by means of a hydrogen bond not a covalent bond.

C. The distal histidine binds iron

This statement is false because the distal histidine is not bonded to iron but to oxygen but stabilizes the oxygen bonded to iron

D. Free heme binds CO with the Fe, C and O atoms in a linear array.

This statement is true because free heme has more affinity for CO than O2 as it has the least steric hindrance when the Fe, C, and O atoms lie in a straight line. On the other hand, when O2 binds to free heme, the axis of the oxygen molecule is positioned at an angle to the Fe-O bond thereby producing significant steric hindrance.

E. The iron in heme binds the oxygen atom of CO.

This statement is false because the iron in heme binds to the carbon atom, C, of CO rather than to oxygen atom.

7 0

3 years ago

What mass of Al would be obtained from the complete reduction of 10.2 tonnes of Al2O3?

Fynjy0 [20]

Answer:

5.4 tonnes.

Explanation:

The first step is to find the molar mass of Al2O3. Aluminum has a molar mass of about 27 and oxygen has a molar mass of about 16, so 2(27)+3(16)= 102g/mol=0.102kg/mol. 10200kg/0.102kg/mol=100,000 moles of Al2O3 in 10.2 tonnes. Multiplying this by the molar mass of the two aluminums, you get a total of 54*100,000=5400000g=5400kg=5.4 tonnes. Hope this helps!

3 0

3 years ago

If the formula for a compound is represented by XY2 and the charge on the Y ion is -2, what is the charge in the X ion?

Georgia [21]

The total charge of a compound must be zero. So the Y ion has charge of -2. Then the charge of X ion+(-2)*2=0. So the charge of X ion is +4.

7 0

4 years ago