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4 years ago

How do you set up a proper experiment

Chemistry

1 answer:

vova2212 [387]4 years ago

5 0

First off, With a hypothesis

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The reaction of ammonium ion with nitrite ion in aqueous solution

Roman55 [17]

Answer:

Rate = k[NH4+][NO2-]

Explanation:

The rate law is the equation that relates the rate of chemical reaction with the concentration or pressure of the reactants. For the above reaction between ammonium ion and nitrite ion in a solution, the rate is dependent on the availability of reactants in the solution.

The ammonium ion is first order and the overall order is second and the rate law is hence written as,

R = k [NH4+][NO2-]

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3 years ago

Which statement is not true of alkenes?

sladkih [1.3K]

Answer:

Explanation:

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4 years ago

What is the definition of Jupiter

Stolb23 [73]

In astronomy, the largest planet recorded in the solar system; the fifth major planet from the sun. Jupiter is largely composed of gases. It is named after the ruler of the Roman Gods. You can find this under Mythology and Folklore. You can see Jupiter from Earth.

*Since my first comment was deleted for supposedly being copied and pasted(which it wasn't) I'm leaving this here. It was NOT copied and pasted!!*

8 0

3 years ago

One of relatively few reactions that takes place directly between two solids at room temperature is Ba(OH)2 · 8H2O + ammonium th

Hatshy [7]

Answer:

$\boxed{\text{3.1 g}}$

Explanation:

We will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 315.46 76.12

Ba(OH)₂·8H₂O + 2NH₄SCN ⟶ Ba(SCN)₂ + 2NH₃ + 10H₂O

m/g: 6.5

1. Moles of Ba(OH)₂·8H₂O

$\text{Moles of Ba(OH)$_{2}\cdot $8H$_{2}$O}\\= \text{ 6.5 g Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}{\text{ 315.46 g Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}$

2. Moles of NH₄SCN

The molar ratio is 2 mol NH₄SCN:1 mol Ba(OH)₂·8H₂O

$\text{Moles of NH$_{4}$SCN} =\text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{2 mol NH$_{4}$SCN}}{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0412 mol NH$_{4}$SCN}$

3. Mass of NH₄SCN

$\text{Mass of NH$_{4}$SCN} = \text{0.0412 mol NH$_{4}$SCN} \times \dfrac{\text{76.12 g NH$_{4}$SCN}}{\text{1 mol NH$_{4}$SCN}} =\\\textbf{3.1 g NH$_{4}$SCN}\\\\\text{You must use }\boxed{\textbf{3.1 g}}\text{ NH$_{4}$SCN}$

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4 years ago

Most important factor in determining an element's place in the periodic table

Monica [59]

The number of Protons.
(which is also the ATOMIC NUMBER)

3 0

3 years ago