Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction 
You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:
The proportion is the equal relationship that exists between two reasons and is represented by: 
This reads a is a b as c is a d.
To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:
Solving for the mass of gold gives:
mass of gold= 5.56 grams
So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>
Answer:
2.99 M
Explanation:
In order to solve this problem we need to keep in mind the definition of molarity:
- Molarity = moles of solute / liters of solution
In order to calculate the moles of solute, we <u>convert 125.6 g of NaF into moles</u> using its <em>molar mass</em>:
- 125.6 g NaF ÷ 42 g/mol = 2.99 mol NaF
As the volume is already given, we can proceed to <em>calculate the molarity</em>:
- Molarity = 2.99 mol / 1.00 L = 2.99 M
Answer:
all 4 of the middle ones are part of the nucleus
Answer:
4.52×10^24
Explanation:
N = n × Na
where; N = no. of bananas
n = no. of moles
Na = Avogadro's constant
Which is 6.02×10^23
N = 7.5 × 6.02×10^23
N =4.515×10^24
Answer: heat
Explanation:
Is that heat boils the liquid and the liquid eventually evaporated into gas
