Explanation:
Moreover, increasing use of fossil fuels also causes serious environmental problems. Hence, there is a pressing need to use renewable energy sources like solar energy, wind, tide, biomass and energy from waste material. (i) it reduces the dependence on fossil fuels for energy. (ii) they donot produces pollution.
Digestive I think, that transfers food.
The balanced equation for the decomposition of hydrogen peroxide is H₂O₂(aq)→2H₂O(l)+O₂(g).
<h3>What is decomposition reaction?</h3>
Decomposition reactions are those reactions in which a compound will decompose into small molecules.
Hydrogen peroxide will decompose into water molecule and oxygen gas, balanced chemical equation will be represented as:
H₂O₂(aq) → 2H₂O(l) + O₂(g)
Where all atoms are present in equal quantities on both side of the equation.
Hence balanced decomposition reaction of H₂O₂ is H₂O₂(aq)→2H₂O(l)+O₂(g).
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Answer:
The energy of the orbitals are the same
Explanation:
For a free metal ion, all the d-orbitals are of the same energy. The five d-orbitals are said to be five fold degenerate in the free metal ion. Hence all the d-orbitals will possess the same energy irrespective of which one is first filled.
In an octahedral or tetrahedral crystal field, the d-orbitals will loose their degeneracy and become different in energy based on their orientation towards the ligands.
Answer:
a) galvanic cell
b)electrolytic cell
c) i) K=6.27x10'34
ΔG°=198790 J
ii) K=3.58x10'-34
ΔG°= 191070 J
d) E°=0.278 v
ΔG°= -26827 J
Explanation:
a) There are two kinds of an electrochemical cell, the first is called "galvanic cells", and the second "electrolytic cell".
The fuel cells are capable of produce electric energy through chemical reactions. These reactions are often spontaneous. So, the galvanic cell has a negative value for Gibbs free energy.
b) The electrolytic cell increases the value of Gibbs energy, to positive values, due to the reactions are not spontaneous.
c) i) look image attached
ii) k = look image attached
ΔG° = -nFE° = - 6 X 95500 J/vmole x (-0.33 v)
ΔG° =-191070
d) E°= 0.0592 v/n x lg K
E°= 0.0592V / 1 X log 5.0X10'4
E°= 0.278 v
ΔG° = -nFE° = -1 x 96500 J/ vmole x 0.278v
ΔG° = -26827 J
