The second law states that the total entropy can never decrese over time for an isolated system
Answer:
x = 0.974 L
Explanation:
given,
length of inclination of log = 30°
mass of log = 200 Kg
rock is located at = 0.6 L
L is the length of the log
mass of engineer = 53.5 Kg
let x be the distance from left at which log is horizontal.
For log to be horizontal system should be in equilibrium
∑ M = 0
mass of the log will be concentrated at the center
distance of rock from CM of log = 0.1 L
now,
∑ M = 0



x = 0.974 L
hence, distance of the engineer from the left side is equal to x = 0.974 L
A fuse melts to protect a circuit.
I'm Pretty sure it's FRICTION
Answer:
A sound wave can be affected by a lot of different variables. As an audio engineer some of the more common things we deal with involve air temperature, humidity and even wind. The first two affect the speed at which the wave travels, while wind can actually cause a phase like effect if it is blowing hard enough. Another big one though not directly related to the air is walls and other solid objects that cause the sound wave to bounce off of them and reflect. This causes a secondary wave that isn’t as strong as the first wave but is the cause of “muddy” sounding venues when you are indoors.
Explanation: