QC Suppose you hear a clap of thunder 16.2s after seeing the associated lightning strike. The speed of light in air is 3.00× 10⁸
1 answer:
If you hear a clap of thunder in a time of 16.2s after seeing the associated lightning strike, you are: 5508 m far from the lightning strike
To solve this problem we must consider that the speed of light is greater than the speed of sound, therefore to calculate the distance we must use the speed of sound (340 m/s).
The formula and procedure we will use to solve this exercise is:
x = v * t
Where:
- x = distance
- t = time
- v = velocity
Information about the problem:
- v(sound) = 340 m/s
- t = 16.2 s
- x=?
Applying the distance formula we have that:
x = v * t
x= 340 m/s * 16.2 s
x = 5508 m
<h3>What is velocity?</h3>It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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Answer:
Its initial position was 471 m.
Explanation:
We have,
Final position of the object is 327 m
Displacement of the object is -144 m
It is required to find its initial position. The difference of final and initial position is equal to the displacement of the object. So,
So, its initial position was 471 m.
Answer:
1.6 x N
Explanation:
If the force between two actual wires has this value, the current is defined to be exactly 1 A.
The force between two parallel wires carrying current can be defined as,
F= μ
L/ 2πd
where,
current = 1Amp
current = 2amp
Length 'L'= 1m
distance 'd'= 2.5m
permeability of free space 'μ'= 4πx N/m
Putting the above values in the equation,
F=( 4πx x 1 x 2 x 1 )/ 2πx2.5
F= 1.6 x N