10 mph i jus got it right on the test
Determinatio/Goal setting
The velocity of the car at the bottom of the hill=19.8 m/s
mass= 100 kg
height= h=20 m
Velocity at the bottom=V
Using the law of conservation of energy
potential energy at top = kinetic energy at the bottom
m g h= 1/2 m v²
g h= 1/2 v²
9.8 (20)=1/2 V²
V=19.8 m/s
Thus the velocity of car at the bottom of hill=19.8 m/s
Answer:
125 m
Explanation:
Given:
v₀ = 20 m/s
v = 0 m/s
a = -1.6 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (20 m/s)² + 2 (-1.6 m/s²) Δy
Δy = 125 m
Refractive index(n)= speed of light in vacuum/ speed of light in medium.
Since refractive index is 1.11, and usually we know that the speed of light is 300,000km/s, simply divide 300,000km/s over 1.11. That is, 270,270.2703 when simply rounding, its 270,270 km/s.
