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denis-greek [22]
3 years ago
13

Force of 10N down,10N to the right,and 5N to the left are acting on a ball .it acceleration horizontally to the right.what other

force,if any,is acting on the ball
Physics
1 answer:
denpristay [2]3 years ago
3 0

Answer:

A 10 N force pointing up

Explanation:

If the net acceleration of the object is horizontal pointing to the right, that means that all vertical forces must have canceled out, and the only ones "unbalanced" are the horizontal ones (10 N to the right minus 5 N to the left giving a net force of 5 N to the right).

Since they mentioned only one vertical force pointing down (10 N), there must be another one of same magnitude but pointing in opposite direction (up).

Then there must also be a 10 N force pointing up acting on the object.

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Which items did Mendeleev write down on note cards while he was observing
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What is the picture of the cards that Mendeleev put on the notes?
4 0
3 years ago
Correct the sentence below to reflect an “I” statement. 
Anarel [89]
The word “you” shouldn’t be used, and I learned the I statement to have your feelings stated, then when, then because, and finally a want. So, to correct this, an appropriate statement would be “ I feel misunderstood when I am treated like a child because my curfew is set for 9:00 pm on the weekends and I want to be seen as your equal and as though you are not superior to me. You can use the word “you” after stating you want something out of the other person.
5 0
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Read 2 more answers
Naturally occurring element X exists in three isotopic forms: X-28 (27.977 amu, 92.23% abundance), X-29 (28.976 amu, 4.67% abund
vova2212 [387]

Answer:

C. 28.09 amu

Explanation:

The natural occurring element exist in 3 isotopic forms: namely X-28 (27.977 amu, 92.23% abundance),  X-29 (28.976 amu, 4.67% abundance) and  X-30 (29.974 amu, 3.10% abundance).

The atomic weight of elements depends on the isotopic abundance. If you know the fractional abundance and the mass of the isotopes the atomic weight can be computed.

The atomic weight is computed as follows:

atomic weight = mass of X-28 × fractional abundance + mass of X-29 × fractional abundance + mass of  X-30 × fractional abundance

atomic weight = 27.977 × 0.9223 + 28.976 × 0.0467 + 29.974 ×  0.0310

atomic weight = 25.8031871 + 1.3531792 + 0.929194

atomic weight = 28.0855603 amu

To 2 decimal place atomic weight = 28.09 amu

6 0
3 years ago
Câu 1. Con lắc lò xo treo thẳng đứng, dao động điều hòa với biên độ 2cm và tần số góc 20 rad/s. Chiều dài tự nhiên của lò xo là
natka813 [3]

Answer:

28 cm and 32 cm

Explanation:

1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of

a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.

As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.

So, the minimum length is 28 cm and the maximum length is 32 cm.

8 0
3 years ago
Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with
Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg               v_a = 2.2 m/s

m_b = 1.6 kg               v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

                                   = 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

v = \sqrt{32.44^2 + (-1.8)^2}

v = 32.49 m/s

tan \theta = \dfrac{-1.8}{32.44}

\theta = tan^{-1}(\dfrac{-1.8}{32.44})

θ = 3.176° (downward with horizontal)

4 0
3 years ago
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