Answer:
x = 2 and x = 1
Step-by-step explanation:
I think
0.2 + 0.3 + 0.5 = 1
190 x 0.2/1 = 38
190 x 0.3/1 = 57
190 x 0.5/1 = 95
190
0.2: 0.3: 0.5
38: 57: 95
1) 110+30+a = 180
a = 180-140 = 40
Obtuse angled triangle
2) 50+50+C = 180
C=180-100 =80
Acute angled triangle
3) 45+45+b =180
b =180-90 = 90
Right angled triangle
4) 45+60+C = 180
C = 180-105 =75
Acute angled triangle
5) 94+47+b =180
b = 180-141=39
Obtuse angled triangle
6)81+53+a = 180
a =180-134 = 46
Acute angled triangle
7) 38+45+b =180
b = 180-83 =97
Obtuse angled triangle
8) 36+54+C =180
C =180-90 = 90
Right angled triangle.
You can use my photo as reference but its going to be 15/100 of 480
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²