Answer:
(4t − 3) (t − 6)
Step-by-step explanation:
Using AC method:
Given a quadratic ax² + bx + c, find factors of ac that add up to b. Divide those factors by a and reduce. The denominators become the coefficients and the numerators become the constants.
Here, a = 4, b = -27, and c = 18.
ac = 4 × 18 = 72
Factors of 72 that add up to -27: -3 and -24
Divide factors by a: -3/4 and -24/4
Reduce: -3/4 and -6/1
So the factored expression is:
(4t − 3) (t − 6)
Answer:
Solution
verified
Verified by Toppr
m
2
−3m−1=0
m
2
−3m=1 → (1)
Third term =(
2
1
coeeficientofm)
2
(
2
1
×(−3))
2
=(
2
−3
)
2
=
4
9
Adding
4
9
to both sides of equation (1), we get
m
2
−3m+
4
9
=1+
4
9
∴ m
2
−3m+
4
9
=
4
4+9
∴ (m−
2
3
)
2
=
4
13
Taking square roots on both sides
∴ m−
2
3
=±
2
13
∴ m=
2
3
+
2
13
or m=
2
3
−
2
13
m=
2
3+
13
,
2
3−
13
are the roots of the given quadratic equation.
Answer:
"k+12" IS greater than 20. If in this hypothetical question.
Step-by-step explanation:
Please brailiest me
P-6=19; p=13
so you just plug the value of P into the problems P and solve the equation
(13) - 6 = 19
7=19
so...that's incorrect because 7 can't equal 19 making the problem No solution. if that's wrong then idk what they're teaching in math any more...
Answer:
x=6
Step-by-step explanation: