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Pachacha [2.7K]
2 years ago
5

Considering only the factors of the form x - k, what is the relationship between the k values and the zeros?​

Mathematics
1 answer:
Fudgin [204]2 years ago
8 0

Given:

Considering only the factors of the form x - k.

To find:

The relationship between the k values and the zeros?​

Solution:

We know that, if (x-c) is a factor of a function f(x), then x=c is a zero of function f(x), i.e., f(c)=0, where, c is a constant.

It is given that, only the factors of the form x - k. Then by using the above theorem we can say that, k values are the zeros of the function.

The relationship between the k values and the zeros is defined as

​k values = Zeros of the function

Therefore, the k values are to zeros of the function.

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What is the percent change from 41 to 95?
igomit [66]

Answer:

131.7%

Step-by-step explanation:

I used <em>https://www.omnicalculator.com/math/percentage-change</em>

5 0
3 years ago
The ratio of Holly's age to that her aunt is 4:9. When holly was born her aunt was 15 years old. How old is holly's aunt now?
Lyrx [107]

Answer:

27 years

Step-by-step explanation:

Let Holly's age be h and Aunt's age be a. We can setup 2 equations and solve.

1. \frac{h}{a}=\frac{4}{9}

2. a - 15 = h

We can plug in equation 2 into equation 1 to solve for aunt's age:

\frac{h}{a}=\frac{4}{9}\\\frac{a-15}{a}=\frac{4}{9}\\9(a-15)=4a\\9a-135=4a\\5a=135\\a=\frac{135}{5}=27

Holly's aunt's age is 27

3 0
3 years ago
Which of the following statements is not true​
almond37 [142]

Answer:

2nd option is the answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In The autumn 40% of the leaves on a tree are yellow and 24% of them are green the remaining 72 leaves are half yellow how many
Charra [1.4K]

Percentage of yellow leaves on a tree during Autumn = 40%

Percentage of green leaves on a tree during Autumn = 24%

Percentage of half yellow leaves on the tree during Autumn :

=  \tt100 - 40 + 24

= \tt 100 - 64

= \tt 36 \%Thus, the percentage of half yellow leaves on the tree during Autumn = 36%

Number of half yellow leaves on the tree = 36%

Let the total number of leaves on the tree be x.

Which means :

=  \tt36 \% \: of \: x = 72

=  \tt \frac{36}{100}  \times x = 72

=  \tt \frac{36 \times x}{100}  = 72

=  \tt \frac{36x}{100}  = 72

= \tt 36x = 72 \times 100

=  \tt36x = 7200

= \tt x =  \frac{7200}{36}

\color{plum} =  \tt \: x = 200

Thus, total number of leaves on the tree = 200

Number of yellow leaves on the tree :

=  \tt40 \% \: \:  of \: \:  200

=  \tt \frac{40}{100}  \times 200

= \tt   \frac{40 \times 200}{100}

= \tt  \frac{8000}{100}

\color{plum}  \tt = 80 \: yellow \:  \: leaves

Thus, total number of yellow leaves on the tree = 80

Number of green trees on the tree :

=  \tt24 \% \:  \: of \:  \: 200

= \tt  \frac{24}{100} \times 200

= \tt  \frac{24 \times 200}{100}

=  \tt \frac{4800}{100}

\color{plum} = \tt 48 \: green \:  \: leaves

Thus, the total number of green leaves on the tree = 48

Since the sum of all types of leaves form 200[80+48+72=200], we can conclude that we have found out the correct number of each type of leaf.

▪︎Therefore, <em>the total number of leaves on the tree = 200</em>

3 0
3 years ago
Someone help me please. I don't just want the answer, I need an explanation on how it's done too.​
NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j)  a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

4 0
2 years ago
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