Answer:
a. Chi-square test of independence
Step-by-step explanation:
The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.
In the given problem the Equal , more or less are the attributes.
The goodness of fit test is applicable when the cell probabilities depend upon the unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
<span>sinx - cosx =sqrt(2)
Taking square on both sides:
</span>(sinx - cosx)^2 =sqrt(2)^2<span>
sin^2(x) -2cos(x)sin(x) + cos^2(x) = 2
Rearranging the equation:
sin^2(x)+cos^2(x) -2cos(x)sin(x)=2
As,
</span><span>sin^2(x)+cos^2(x) = 1
</span><span>So,
1-2sinxcosx=2
1-1-2sinxcosx=2-1
-</span><span>2sinxcosx = 1
</span><span>Using Trignometric identities:
-2(0.5(sin(x+x)+sin(x-x))=1
-sin2x+sin0=1
As,
sin 0 = 0
So,
sin2x+0 = -1
</span><span>sin2x = -1</span><span>
2x=-90 degrees + t360
Dividing by 2 on both sides:
x=-45 degrees + t180
or 2x=270 degrees +t360
x= 135 degrees + t180 where t is integer</span>
Answer:
5850
Step-by-step explanation:
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-- 500 centimeters = 5 meters
-- 0.005 kilometers = 5 meters
-- 5,000,000,000 nanometers = 5 meters
Answer:
Mr Wilburn
Step-by-step explanation:
Ms L = 30/45 = 0.67 assignments per minute
Mr W = 45/60 = 0.75 assignments per minute