Which graph represents the function f(x) = 2 · 4^x ?

Mathematics

1 answer:

NARA [144]3 years ago

7 0

Answer:

The fisrt one were it almost hits 3

Step-by-step explanation:

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Please Help.(picture below) 30 points

Sveta_85 [38]

Answer = B = 376 degrees - 3x

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3 years ago

Read 2 more answers

The classrooms are trying to raise $1,200.00 for charity.

Svetradugi [14.3K]

Answer:

The classes need to raise $164.86 more to reach their goal of $1200.

Step-by-step explanation:

$1,200 total

Mrs. LeBlanc's class has raised 50% of the total, so they've raised $600.

1200/2 = 600

Mr. Patel's class has raised $235.14.

235.14 + 600 = 835.14

Ms. Warner's class has raised 1/3 of the total of Mrs. LeBlanc's class ($600), so they've raised $200.

600/3 = 200

835.14 + 200 = 1035.14

The three classes have raised a combined total of $1035.14.

1200 - 1035.14 = 164.86

The classes need to raise $164.86 more to reach their goal of $1200.

5 0

3 years ago

An Internet service provider offers a plan that allows a subscriber to download 2 GB or less of content per month. Define a vari

Eddi Din [679]

Answer: Choice C

$0 \le d \le 2$

Graph with filled in circles at d = 0 and d = 2, shading in between

==========================================

Explanation:

d = amount downloaded in gigabytes

The smallest amount is d = 0. We cannot download a negative amount of data, so this is why d = 0 is the smallest.

The largest amount allowed is d = 2. This is the cap that the ISP has set up.

So basically d can be anything between d = 0 and d = 2, including both endpoints. This means $0 \le d \le 2$

We use filled in circles for both endpoints to show to the reader "include these endpoints". Shading is done in between to show the entire solution set of possible d values. For instance d = 1 is in that region so it is possible to have this solution. Something like d = 4 is outside the region and not possible.

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3 years ago

Rewrite the expression in the form z^n.<br> z^3/4 x z^2

grin007 [14]

Step-by-step explanation:

here's the answer to your question