Answer:
Surface area of the cube = 6cm²
Volume of the cube = 1cm³
Explanation:
The surface area of a cube, which refers to the sum of all the areas of the faces of the cube can be calculated using the formula:
S.A = 6 × a²
That is; a² + a² + a² + a² + a² + a²
Where;
a = length of a side of a cube
a² = area of one side of a cube
Note that, a cube has 6 faces
According to this question, a cube has a length of 1cm on each side.
Hence, S.A = 6 × 1²
S.A = 6 × 1
S.A = 6cm²
Volume of the cube can be calculated using the formula: a³
Where a = 1
Volume = 1 × 1 × 1
Volume = 1cm³
Answer:
What is the problem... nothing is listed??
Explanation:
Answer:
B. As the distance between loci increases, some multiple crossovers go undetected such that the relationship between recombination frequency and map distance ceases to be linear.
Explanation:
When calculating recombination frequencies, and hence, map distances, we might notice that these distances are not completely additive. They might vary. <em>For example, let us say that we have three genes, A, B, and C, in that order. </em>We calculated that the <em>distance between A and B equals 5.9</em> MU and that <em>B and C are 19.5 MU apart.</em> According to this, we might say that the <em>total distance between A and C is 25.4 MU (5.9 + 19.5). </em>However, after a<em> two-point calculation between A and C, the value equals 23.7 MU. </em>
The recombination frequency between these two genes located in the extremes and far apart underestimate the actual genetic distances between them because there might occur other crossing-overs that were not detected. This is <em>when calculating the distance between A and C, we probably will not detect the occurrence of a double recombinant between them, and hence, we might sub-estimate the real distance.</em>
The relationship between the actual map distance (number of crossing overs) and the recombination frequency between two loci, is not lineal. The farther apart are the two genes, the worse is the distance estimation.
Answer:
The centromeres split apart
Explanation:
Telophase is the last sage of cell cycle that ultimately result in the formation of daughter cells. The chromosome become more condense in this stage.
The nuclear envelope reconstructed and the cyotkinesis is under way in the telophase. The nucleolus reforms in the telophase. The centromeres are split part in the anaphase stage of the cell cycle.
Thus, the correct answer is option (3).
