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Vera_Pavlovna [14]
3 years ago
5

What are two factors that ultimately decide what organisms can live in an area?

Biology
1 answer:
victus00 [196]3 years ago
4 0

Answer:

abiotic and biotic factors

Explanation:

abiotic factors are things like sunlight, soil, minerals, ect.

biotic factors are things like plants, animals, fungi, ect.

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Embryos of different species look very similar, which shows that the organisms share a BLANK ancestor.
Zarrin [17]

Answer:

Ancestor

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How would the human population be different if crossing over did not happer during meiosis?
natta225 [31]

Answer:

Without crossing over, each chromosome would be either maternal or paternal, greatly reducing the number of possible genetic combinations, which would greatly reduce the amount of genetic variation between related individuals and within a species

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3 years ago
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The dna structures ​
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Each DNA strand is composed of nucleotides—units made up of a sugar (deoxyribose), a phosphate group, and a nitrogenous base. Each strand of DNA is a polynucleotide composed of units called nucleotides. A nucleotide has three components: a sugar molecule, a phosphate group, and a nitrogenous base. Explanation:

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Humerus bones from the same species of animal have approximately the same length-to-width ratios. It is known that Species A has
Dima020 [189]

Answer:

The unearthed Humerous bones don't belong to the species A.

Explanation:

Hello!

You are studying the Humerus bones species A, who is known to have a mean ratio of 8,5. This value corresponds to the population mean of the length-to-with ratio of bones of species A, symbolized as μ.

The hypothesis you want to study is "The Humorous bones unearthed belong to the species A" if you assume this to be true, then the mean of the length-to-with ratio should be equal to the known population mean of the length-to-with ratio.

Symbolized:

H₀: μ = 8,5

H₁: μ ≠ 8,5

Significance level: α: 0,05

You are asked to use a Z-test, since you don't know the value of the population variance, but have the sample values, the sample size is big enough (more than n=30). Assuming that the sample values are independent, the statistic test of choice is the approximation:

Z= \frac{x_bar-μ}{S\sqrt[]{n} }≅N(0;1)

The critical region, in this case, it's a two-tailed test (remember the type is determined by the null hypothesis) so you'll have two critical values.

Left value [/tex]Z_{\alpha/2} = Z_{0,025} = -1,96

Right value Z_{1-\alpha/2} = Z_{0,975} = 1,96So you'll reject the null hyphotesis if the calculated [tex]Z_{obs} value is ≤-1,96 or ≥1,96 and you'll support it if -1,96<Z_{obs}<1,96

Now we calculate the statistic by replacing the formula with the data:

x_bar = 9,26

S = 1,20

n = 41

Z_{obs}= \frac{x_bar-μ}{S\sqrt[]{n} }

Z_{obs}= \frac{9,26-8,5}{1,20\sqrt[]{41} }

Z_{obs}= 4,0553

Since the calculated value falls in the rejection region, this means, you have statistically significant results. In other words you can reject the null hipothesis (H₀: μ = 8,5) and asume that the unearthed Humerous bones don't belong to the species A.

I hope you have a SUPER day!

7 0
3 years ago
one of the carbon compounds found in a cell has twice as many hydrogen atoms as oxygen atoms, this compound most likeley belongs
andriy [413]
Carbohydrates is your answer
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