Clarissa (the surveyor from our book) is at home and needs to figure out how tall her wall is in order to replace one of the lig
1 answer:
Answer:
The height of the wall is 18 ft.
Step-by-step explanation:
I have taken a look at the question, and will label the diagram accordingly. Check the attachment.
We are asked to calculate the height of the wall. Well, the incidence ray is equal to the reflected ray, so therefore by AA we have similar triangles. Setting up a proportion to determine the height of the wall:
9/6 = 27/x [where x = height of the wall]
x = 27*6/9 = 18 ft.
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Answer:
1 and 2.
Midpoints calculated, plotted and connected to make the triangle DEF, see the attached.
- D= (-2, 2), E = (-1, -2), F = (-4, -1)
3.
As per definition, midsegment is parallel to a side.
Parallel lines have same slope.
<u>Find slopes of FD and CB and compare. </u>
- m(FD) = (2 - (-1))/(-2 -(-4)) = 3/2
- m(CB) = (1 - (-5))/(1 - (-3)) = 6/4 = 3/2
- As we see the slopes are same
<u>Find the slopes of FE and AB and compare.</u>
- m(FE) = (-2 - (- 1))/(-1 - (-4)) = -1/3
- m(AB) = (1 - 3)/(1 - (-5)) = -2/6 = -1/3
- Slopes are same
<u>Find the slopes of DE and AC and compare.</u>
- m(DE) = (-2 - 2)/(-1 - (-2)) = -4/1 = -4
- m(AC) = (-5 - 3)/(-3 - (-5)) = -8/2 = -4
- Slopes are same
4.
As per definition, midsegment is half the parallel side.
<u>We'll show that FD = 1/2CB</u>
- FD =
=
=
- CB =
=
= 2
- As we see FD = 1/2CB
<u>FE = 1/2AB</u>
- FE =
=
=
- AB =
=
= 2
- As we see FE = 1/2AB
<u>DE = 1/2AC</u>
- DE =
=
=
- AC =
=
= 2
- As we see DE = 1/2AC
Answer:
The domain of the graph must be .
Therefore,
Hence, option a is true.
Step-by-step explanation:
From the graph, it is clear that the graph is heading towards positive infinity from x=-4.
The point x=-4 is included in the graph as the starting point of the graph i.e. x=4 is showing a closed circle on x=4, and heading towards positive infinity onward.
i.e. [-4, ∞)
Hence, the domain of the graph must be .
Therefore,
Hence, option a is true.