Answer:
Wherever the slope is increasing or decreasing the sharpest.
Explanation:
In a distance v time graph, the slope is the speed. So the sharper the slope, the faster the object is going.
I think B would be the best answer
<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2>
<h2>
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DATA:</h3>
Range = R = 78m
Initial Velocity = 
= 30m/s
Angle(theta) = ?
<h2>_____________________________________</h2><h3>SOLUTION:</h3>
The Range is given by,
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
The minimum value of the coefficient of static friction between the block and the slope is 0.53.
<h3>Minimum coefficient of static friction</h3>
Apply Newton's second law of motion;
F - μFs = 0
μFs = F
where;
- μ is coefficient of static friction
- Fs is frictional force
- F is applied force
μ = F/Fs
μ = F/(mgcosθ)
μ = (250)/(50 x 9.8 x cos15)
μ = 0.53
Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.
Learn more about coefficient of friction here: brainly.com/question/20241845
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The answer is B hope this helped
