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mote1985 [20]
2 years ago
14

A 50-kg block is at rest on a 15o slope. A force of 250 N is acting on the block up the slope parallel to it. If the block does

not slide up the slope, what is the minimum value of the coefficient of static friction between the block and the slope
Physics
1 answer:
Iteru [2.4K]2 years ago
6 0

The minimum value of the coefficient of static friction between the block and the slope is 0.53.

<h3>Minimum coefficient of static friction</h3>

Apply Newton's second law of motion;

F - μFs = 0

μFs = F

where;

  • μ is coefficient of static friction
  • Fs is frictional force
  • F is applied force

μ = F/Fs

μ = F/(mgcosθ)

μ = (250)/(50 x 9.8 x cos15)

μ = 0.53

Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.

Learn more about coefficient of friction here: brainly.com/question/20241845

#SPJ1

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A steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to whic
MAVERICK [17]

The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.

<h3>Linear expansivity </h3>

The temperature to which it must be heated in order to fit the shaft is calculated as follows;

\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}

where;

  • ΔT is change in temperature
  • ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
  • α is coefficient of linear expansion
  • L is original length

ΔT = (0.04)/(50 x 15 x 10⁻⁶)

ΔT = 53.3 ⁰C

<h3>Final temperature</h3>

T₂ - T₁ = ΔT

T₂ = ΔT + T₁

where;

  • T₂ is final temperature
  • T₁ is initial temperature

T₂ = 53.3 + 20

T₂ = 73.33 ⁰C

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4 0
2 years ago
The temperature of 2.0 g of helium is increased at constant volume by ΔT. What mass of oxygen can have its temperature increased
gavmur [86]

Answer:

m = 9.6 g

Explanation:

Thermal energy given to helium gas at constant volume is given as

Q = nC_v \Delta T

so here we have

C_v = \frac{3}{2}R

n = moles

n = \frac{2}{4} = 0.5

so we have

Q = \frac{3}{2}R(0.5)\Delta T

now we know that

for oxygen gas we have

C_v = \frac{5}{2}R

for same amount of heat we have

Q = nC_v \Delta T'

\frac{3}{2}R(0.5)\Delta T = \frac{m}{32} (\frac{5R}{2}) \Delta T

m = \frac{0.75 \times 32}{2.5}

m = 9.6 g

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3 years ago
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The most abundant state of matter in the universe is also the state with the most kinetic energy. That is
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Plasma is the most abundant state of matter in the universe and has the most kinetic energy. It can be found in all the planets of our solar system, the sun, and other stars

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In general, the further planets are from the sun, the cooler they are. what other factor can have a significant influence on a p
valkas [14]

The factor that can have a significant influence on a planet’s surface temperature is its atmosphere.

<h3>What is the role of the atmosphere in the planet's temperature?</h3>

The atmosphere plays a fundamental role in the Earth planet's temperature because it allows the entry and out of certain types of radiation that may increase the temperature.

The role of the atmosphere in the Earth's temperature is well documented because our temperature is thick and it increases its homeostatic temperature balance.

In conclusion, the factor that alters a planet’s surface temperature is its atmosphere.

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