All categories

4 years ago

How can you tell which part of the graph resulted from the fastest speed in a d vs. t plot?

Physics

1 answer:

Art [367]4 years ago

6 0

Answer:

Wherever the slope is increasing or decreasing the sharpest.

Explanation:

In a distance v time graph, the slope is the speed. So the sharper the slope, the faster the object is going.

You might be interested in

An 1,840 W toaster, a 1,380 W electric frying pan, and a 70 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (T

Pavlova-9 [17]

Answer with Explanation:

We are given that

Power of toaster= $P_1=1840 W$

Power of electric frying pan= $P_2=1380 W$

Power of lamp= $P_3=70 W$

Current in circuit=15 A

Potential difference= V=120 V

We know that

Current= $\frac{P}{V}$

Using the formula

Current drawn by toaster= $I_1=\frac{1840}{120}=15.3 A$

Current drawn by electric frying pan= $I_2=\frac{1380}{120}=11.5 A$

Current drawn by lamp= $I_3=\frac{70}{120}=0.58 A$

5 0

3 years ago

Which statement is true because of Newton's second law?

expeople1 [14]

Newton's second law of motion says

Force = (mass) x (acceleration) .

<span>B. When the net force ACTING ON an object decreases,
the object's acceleration decreases.</span>

6 0

3 years ago

Read 2 more answers

A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.

pogonyaev

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

$F=\mu N$

where

$\mu$ is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is $\mu=0.012$ . The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

$N=65 N+52 N=117 N$

Therefore, the frictional force is

$F=\mu N=(0.012)(117 N)=1.40 N$

3 0

3 years ago

Space debris left from old satellites and their launchers is becoming a hazard to other satellites. (a) Calculate the speed of a

Pie

Answer:

Part a)

$v = 7407.1 m/s$

Part b)

$v_{rel} = 1.05 \times 10^4 m/s$

Explanation:

Part a)

As we know that orbital velocity at certain height from the surface of Earth is given as

$v = \sqrt{\frac{GM}{R+h}}$

here we know that

$M = 5.98 \times 10^{24} kg$

$R = 6.37 \times 10^6 m$

$h = 900 km = 9.0 \times 10^5 m$

now we have

$v = \sqrt{\frac{(6.67 \times 10^{-11})(5.98 \times 10^{24})}{6.37 \times 10^6 + 9.0 \times 10^5}}$

$v = 7407.1 m/s$

Part b)

When a loose rivet is moving in same orbit but at 90 degree with the previous orbit path then in that case the relative speed of the rivet with respect to the satellite is given as

$v_{rel} = \sqrt{2} v$

$v_{rel} = 1.05 \times 10^4 m/s$

6 0

3 years ago

Light travels fastest when moving through

vitfil [10]

A vaccum unlike sound,light can travel through any matter including a great vacuum of nothing (space)

4 0

3 years ago